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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
3
votes
1
answer
114
views
Suprema of lower density of sums and products of sets with lower density 0
We define the lower density of a set $A\subseteq \mathbb{N}$ by
$$
\operatorname{ld}(A) \ := \ \liminf_{n\to\infty}\frac{|A\cap\{1,\ldots,n\}|}{n}.
$$
For $A,B\subseteq \mathbb{N}$, we set
$$
A + …
3
votes
0
answers
240
views
Density of set of unique sums
Set $U_1 = \{1,2\}$, and for $n\in\mathbb{N}$ with $n\geq 1$ we set $U_{n+1} = U_n\cup A_n$ where $A_n$ is the set of elements of $\mathbb{N}$ that are not in $U_n$ but can be uniquely written as a su …
9
votes
2
answers
437
views
Lower density of numbers not summable by consecutive integers
Let us call a positive integer $n\in\mathbb{N}$ consecutively summable if there are positive integers $m, k < n$ such that $$n=\sum_{i=0}^k (m+i).$$For $A\subseteq \mathbb{N}$ we set the lower density …
4
votes
1
answer
267
views
Size of finite subset of $\mathbb{N}$ such that the sum of reciprocals is a given positive i...
Let $\mathbb{N}$ denote the set of positive integers. For every integer $k\in\mathbb{N}$ let $m(k)$ denote the minimal size of a finite set $S\subseteq \mathbb{N}$ such that $\sum_{j\in S}j^{-1}=k$.
…
7
votes
1
answer
241
views
On subsets of $\mathbb{N}$ reciprocally summable to $1$
Let $\mathbb{N}$ denote the set of positive integers. If $A\subseteq \mathbb{N}$ is finite, we say that $A$ is reciprocally summable to $1$ ("rs1") if $\sum_{a\in A} \frac{1}{a} = 1$.
If $A\subseteq …
-1
votes
1
answer
218
views
Function on quadratic numbers
Let $\mathbb{N}$ denote the set of the positive integers. We consider the following function $f:\mathbb{N}\times \mathbb{N}\to \mathbb{Q}$: $$f(a,b)=\frac{a^2+b^2}{1+ab} \text{ for all } a,b\in\mathbb …
3
votes
1
answer
165
views
Bounded gaps between powers
Let $P = \{n^k: n,k\in\mathbb{N}\setminus\{0,1\}\}$ denote the set of powers. For any $n,r\in\mathbb{N}$ we set $B_r(n)=\{m\in\mathbb{N}: |m-n| \leq r\}$.
Is there a "global" constant $K\in\mathbb{N …
-1
votes
2
answers
150
views
Numbers of the form $2^ma + 2^nb$ where $\text{gcd}(a,b) = 1$ [closed]
Given positive integers $a,b\in\mathbb{N}$ with ${\text gcd}(a,b) = 1$, and given a positive integer $d$, are there necessarily positive integers $m,n$ such that $d \;| \; (2^ma + 2^nb)$?
2
votes
1
answer
215
views
Integers $b$ such that $n \nmid (b^n-1)$ for $n>1$
The number $2$ has the interesting property that whenever $n>1$ is an integer, then $n \nmid (2^n-1)$. (It's a good exercise to prove this statement.)
Let's call a positive integer $b$ $2$-like if fo …
0
votes
0
answers
112
views
Asymptotic behavior of median of number of prime divisors
Let $\mathbb{N}$ denote the set of positive integers, and let ${\bf P}\subseteq {\mathbb N}$ be the set of prime numbers. For $a\in \mathbb{N}$ let $$p(a) = \{p\in {\bf P}: (\exists k\in\mathbb{N})k\c …
1
vote
1
answer
332
views
Powers modulo a fixed integer
We say that a set $A\subseteq \mathbb{N}$ has positive measure if $$\text{lim inf}_{n\to\infty}\frac{|A\cap\{1,\ldots,n\}|}{n} > 0.$$
For $b\in\mathbb{N}$ with $b>1$ we consider the sets $$S_b := \bi …
1
vote
0
answers
371
views
Fermat's Last Theorem in $\mathbb{Z}/n\mathbb{Z}$
Let $\mathbb{N}$ denote the set of positive integers.
We define a relation $R\subseteq \mathbb{N}^3$ by
$$ R = \{(x,y,z) \in \mathbb{N}^3: \exists n\in \mathbb{N}: 1< n \leq \max\{x,y,z\} \land \exi …
5
votes
2
answers
465
views
Approximating integers with prime quotients [closed]
Is this statement true for all positive integers $n\in\mathbb{N}$?
For all $\varepsilon >0$ there are prime numbers $p,q$ such that $|\frac{p}{q} - n| < \varepsilon$.
6
votes
2
answers
777
views
Generalizing Ramanujan's "1729 story"
Whenever I read the anecdote about Hardy, Ramanujan and the taxi number 1729 I'm amazed that it could have occurred to anyone just off the top of their head that 1729 can be written as the sum of two …
0
votes
1
answer
147
views
Prime-less intervals $[n,\lfloor q\cdot n\rfloor]$ for $q\in \mathbb{Q}, q>1$
Is there $q\in\mathbb{Q}$ with $q>1$ and the following property?
There are infinitely many $n\in\mathbb{N}$ such that there are no primes in $[n,\lfloor q\cdot n\rfloor]$.