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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

3 votes
1 answer
114 views

Suprema of lower density of sums and products of sets with lower density 0

We define the lower density of a set $A\subseteq \mathbb{N}$ by $$ \operatorname{ld}(A) \ := \ \liminf_{n\to\infty}\frac{|A\cap\{1,\ldots,n\}|}{n}. $$ For $A,B\subseteq \mathbb{N}$, we set $$ A + …
Dominic van der Zypen's user avatar
3 votes
0 answers
240 views

Density of set of unique sums

Set $U_1 = \{1,2\}$, and for $n\in\mathbb{N}$ with $n\geq 1$ we set $U_{n+1} = U_n\cup A_n$ where $A_n$ is the set of elements of $\mathbb{N}$ that are not in $U_n$ but can be uniquely written as a su …
Dominic van der Zypen's user avatar
9 votes
2 answers
437 views

Lower density of numbers not summable by consecutive integers

Let us call a positive integer $n\in\mathbb{N}$ consecutively summable if there are positive integers $m, k < n$ such that $$n=\sum_{i=0}^k (m+i).$$For $A\subseteq \mathbb{N}$ we set the lower density …
Dominic van der Zypen's user avatar
4 votes
1 answer
267 views

Size of finite subset of $\mathbb{N}$ such that the sum of reciprocals is a given positive i...

Let $\mathbb{N}$ denote the set of positive integers. For every integer $k\in\mathbb{N}$ let $m(k)$ denote the minimal size of a finite set $S\subseteq \mathbb{N}$ such that $\sum_{j\in S}j^{-1}=k$. …
Dominic van der Zypen's user avatar
7 votes
1 answer
241 views

On subsets of $\mathbb{N}$ reciprocally summable to $1$

Let $\mathbb{N}$ denote the set of positive integers. If $A\subseteq \mathbb{N}$ is finite, we say that $A$ is reciprocally summable to $1$ ("rs1") if $\sum_{a\in A} \frac{1}{a} = 1$. If $A\subseteq …
Dominic van der Zypen's user avatar
-1 votes
1 answer
218 views

Function on quadratic numbers

Let $\mathbb{N}$ denote the set of the positive integers. We consider the following function $f:\mathbb{N}\times \mathbb{N}\to \mathbb{Q}$: $$f(a,b)=\frac{a^2+b^2}{1+ab} \text{ for all } a,b\in\mathbb …
Dominic van der Zypen's user avatar
3 votes
1 answer
165 views

Bounded gaps between powers

Let $P = \{n^k: n,k\in\mathbb{N}\setminus\{0,1\}\}$ denote the set of powers. For any $n,r\in\mathbb{N}$ we set $B_r(n)=\{m\in\mathbb{N}: |m-n| \leq r\}$. Is there a "global" constant $K\in\mathbb{N …
Dominic van der Zypen's user avatar
-1 votes
2 answers
150 views

Numbers of the form $2^ma + 2^nb$ where $\text{gcd}(a,b) = 1$ [closed]

Given positive integers $a,b\in\mathbb{N}$ with ${\text gcd}(a,b) = 1$, and given a positive integer $d$, are there necessarily positive integers $m,n$ such that $d \;| \; (2^ma + 2^nb)$?
Dominic van der Zypen's user avatar
2 votes
1 answer
215 views

Integers $b$ such that $n \nmid (b^n-1)$ for $n>1$

The number $2$ has the interesting property that whenever $n>1$ is an integer, then $n \nmid (2^n-1)$. (It's a good exercise to prove this statement.) Let's call a positive integer $b$ $2$-like if fo …
Dominic van der Zypen's user avatar
0 votes
0 answers
112 views

Asymptotic behavior of median of number of prime divisors

Let $\mathbb{N}$ denote the set of positive integers, and let ${\bf P}\subseteq {\mathbb N}$ be the set of prime numbers. For $a\in \mathbb{N}$ let $$p(a) = \{p\in {\bf P}: (\exists k\in\mathbb{N})k\c …
Dominic van der Zypen's user avatar
1 vote
1 answer
332 views

Powers modulo a fixed integer

We say that a set $A\subseteq \mathbb{N}$ has positive measure if $$\text{lim inf}_{n\to\infty}\frac{|A\cap\{1,\ldots,n\}|}{n} > 0.$$ For $b\in\mathbb{N}$ with $b>1$ we consider the sets $$S_b := \bi …
Dominic van der Zypen's user avatar
1 vote
0 answers
371 views

Fermat's Last Theorem in $\mathbb{Z}/n\mathbb{Z}$

Let $\mathbb{N}$ denote the set of positive integers. We define a relation $R\subseteq \mathbb{N}^3$ by $$ R = \{(x,y,z) \in \mathbb{N}^3: \exists n\in \mathbb{N}: 1< n \leq \max\{x,y,z\} \land \exi …
Dominic van der Zypen's user avatar
5 votes
2 answers
465 views

Approximating integers with prime quotients [closed]

Is this statement true for all positive integers $n\in\mathbb{N}$? For all $\varepsilon >0$ there are prime numbers $p,q$ such that $|\frac{p}{q} - n| < \varepsilon$.
Dominic van der Zypen's user avatar
6 votes
2 answers
777 views

Generalizing Ramanujan's "1729 story"

Whenever I read the anecdote about Hardy, Ramanujan and the taxi number 1729 I'm amazed that it could have occurred to anyone just off the top of their head that 1729 can be written as the sum of two …
Dominic van der Zypen's user avatar
0 votes
1 answer
147 views

Prime-less intervals $[n,\lfloor q\cdot n\rfloor]$ for $q\in \mathbb{Q}, q>1$

Is there $q\in\mathbb{Q}$ with $q>1$ and the following property? There are infinitely many $n\in\mathbb{N}$ such that there are no primes in $[n,\lfloor q\cdot n\rfloor]$.
Dominic van der Zypen's user avatar

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