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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

3 votes
0 answers
406 views

Semisimple Lie algebras and the commutator algebra

Suppose $A$ is a associative unital $k$-algebra, where $\operatorname{char}k=0$. As is well-known, $A$ becomes a Lie algebra with respect to the commutator bracket $[x, y] = xy-yx$ for $x,y \in A$. Le …
Paul Gilmartin's user avatar
3 votes

On a dual of Kaplansky's $2^{nd}$ conjecture: admissible algebras?

In regards to your first question: I don't believe there is a way of telling in general whether or not an arbitrary algebra $A$ admits a Hopf structure. There are, however, in certain settings, some c …
Paul Gilmartin's user avatar
11 votes
0 answers
402 views

Lazard's theorem and Hopf structures on the polynomial algebra

Let $k$ be an algebraically closed field of characteristic $0$. A well-known result of Lazard's states that an algebraic group which is isomorphic as a variety to an affine space is unipotent (M. Laz …
Paul Gilmartin's user avatar
6 votes
Accepted

Bialgebraic structure of Sklyanin algebra

In response to your first question, there is no Hopf structure on any Sklyanin algebra of any dimension. See Corollary 2.8 (i) of the following paper: https://arxiv.org/pdf/1601.06687v1.pdf
Paul Gilmartin's user avatar
3 votes

Classifying Hopf algebras that admit a single irreducible comodule

There have been several papers published on such Hopf algebras (which are referred to as "connected" Hopf algebras) over the past decade. In particular, over an algebraically closed field of character …
Paul Gilmartin's user avatar