Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with compactness
Search options not deleted
user 54610
3
votes
Why the intersection of a scott open (or \w the relatively compactness property) filter on a...
We have (only) to prove that for every open set $A\supseteq P$, where $P=\bigcap F$, we have $A\in F$ (for the whole notation you can see the question).
The missing step.
(we refer to [3], thanks to t …
- 163
2
votes
2
answers
346
views
Why the intersection of a scott open (or \w the relatively compactness property) filter on a...
We say that $F$ has the relatively compactness property if for all $A\in F$ exist $B\in F$ s.t. $B\ll A$. … In any case if you use the relatively compactness instead of the scott openness to find a (simpler) proof... it will be fine for me!
Thank you all,
Corrado.
References. …
- 163