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8
votes
2
answers
458
views
Square root for Hamiltonian diffeomorphisms
Let $\psi_t: X\to X$, $t \in [0,1]$, be a path Hamiltonian diffeomorphism on a symplectic manifold $X$, given by functions $H_t$. If $H_t \equiv H$ is independent of $t$ then
$$ \psi_1 = \psi_{\frac …
6
votes
3
answers
2k
views
Symplectic blow-up
Blow-ups of points can also be performed in the symplectic category; for a given point $p\in (X,\omega)$ we choose a Darboux chart around $p$ and then use the symplectic cut corresponding to the stand …
5
votes
0
answers
301
views
Symplectic sum and Symplectic cut
The symplectic sum of Gompf and the symplectic cut of Lerman are known to be inverse of each other, in the sense that if you apply one of these first and the other one afterward, you obtain the origin …
4
votes
1
answer
559
views
On Lerman's description of symplectic cut
Assume $(X,\omega)$ is a compact real $2n$-dimensional symplectic manifold with a Hamiltonian torus action corresponding to the moment map $\mu:X\to \mathfrak{t}^*\cong \mathbb{R}^k$.
In this situati …
4
votes
1
answer
169
views
Complement of Donaldson divisors in dimension 4
Let $(X,\omega)$ be a symplectic 4-manifold such that $\omega$ has a rational cohomology class. I am interested in Donaldson divisors (surfaces) $D$ in $(X,\omega)$ whose complement is a 1-handle body …
3
votes
Square root for Hamiltonian diffeomorphisms
I got this answer from Dusa McDuff (and she got it from some body else):
Suppose given $f:[0,1]\to [0,1]$ such thqt 0 is repelling fixed point and 1 is attracting fixed point and there are no others. …
1
vote
1
answer
171
views
Moser's argument for loops
Let $(\omega_t)_{t\in [0,1]}$ be a path of cohomologous symplectic forms on $X$. The standard Moser's argument shows that there exists a family of diffeomorphisms $(\psi_t)_{t\in [0,1]}$ of $X$ with $ …