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Hamiltonian systems, symplectic flows, classical integrable systems
0
votes
Why we have to fix markers in SFT?
The reason is related to orientations, and more
specifically to bad orbits (see the end of paper :Coherent orientation in SFT).
Assume that a holomorphic curve is asymptotic to a bad
orbit ( means $ …
2
votes
2
answers
608
views
Why we have to fix markers in SFT?
In Symplectic field theory ( Hofer-Eliashberg....) and considering moduli of J-holomorphic curves asymptotic to Reeb orbits at punctures (J-holomorphic curve into a symplectic cobordism),
The authors …
2
votes
Contact structure on a circle bundle over a symplectic manifold.
Let me explain my reason:
Let's $w$ be the symplectic structure on D and $\tilde{w}$ be the one on total space of line bundle . Then we have Gysin exact sequence above which gives $H^2(V)=H^2(D)/ \le …
4
votes
2
answers
627
views
Looking for almost complex structure on a contact manifold invariant under flow of Reeb vect...
Notations : Suppose V is a closed contact compact manifold with contact form $\alpha$, of dimension 2n+1. Consider the symplectic sub-bundle $ \xi \subset TV $ given by $ \xi=$ ker($\alpha$). So $ \xi …
4
votes
2
answers
872
views
Contact structure on a circle bundle over a symplectic manifold.
Consider a Symplectic manifold D (with $H^1(D)=0$) with symplectic form $w$.
Let V be the total space of a circle bundle over D with non-trivial Euler class $e\in H^2(D)$.
You may think of V as the se …
2
votes
Do there exist closed symplectic manifolds with Euler characteristic zero?
Also there are C.Y 3-folds with this property constructed via toric geometry (I think due to Batyrev)
4
votes
1
answer
559
views
On Lerman's description of symplectic cut
Assume $(X,\omega)$ is a compact real $2n$-dimensional symplectic manifold with a Hamiltonian torus action corresponding to the moment map $\mu:X\to \mathfrak{t}^*\cong \mathbb{R}^k$.
In this situati …
5
votes
0
answers
301
views
Symplectic sum and Symplectic cut
The symplectic sum of Gompf and the symplectic cut of Lerman are known to be inverse of each other, in the sense that if you apply one of these first and the other one afterward, you obtain the origin …
6
votes
3
answers
2k
views
Symplectic blow-up
Blow-ups of points can also be performed in the symplectic category; for a given point $p\in (X,\omega)$ we choose a Darboux chart around $p$ and then use the symplectic cut corresponding to the stand …
8
votes
2
answers
458
views
Square root for Hamiltonian diffeomorphisms
Let $\psi_t: X\to X$, $t \in [0,1]$, be a path Hamiltonian diffeomorphism on a symplectic manifold $X$, given by functions $H_t$. If $H_t \equiv H$ is independent of $t$ then
$$ \psi_1 = \psi_{\frac …
3
votes
Square root for Hamiltonian diffeomorphisms
I got this answer from Dusa McDuff (and she got it from some body else):
Suppose given $f:[0,1]\to [0,1]$ such thqt 0 is repelling fixed point and 1 is attracting fixed point and there are no others. …
7
votes
1
answer
357
views
Positive-dimensional Seiberg-Witten moduli spaces
I am looking for examples of (symplectic or not) 4-dimensional manifolds $X$ that have positive dimensional Seiberg-Witten moduli spaces (and $b^{2+}>1$).
Of course, the result/conjecture is that the …
5
votes
1
answer
304
views
Looking for a special rank 2 vector bundle
Let $E\to C$ be a rank $2$, degree $2g-2$, holomorphic vector bundle over a curve of genus $g$.
By Riemann-Roch theorem,
$$H^0(E)-H^1(E)= \deg(E)+2.(1-g)=0. $$
Question: For which $g$, there is such …
2
votes
1
answer
707
views
isotropic deformation retract of Weinstein manifolds?
I found the following paragraph in the paper " Intro to symplectic field theory "
which I don't understand what does it mean precisely?
Suppose W is a symplectic (or Kahler) manifold.
D, smooth divis …
4
votes
1
answer
364
views
balanced curves in Calabi-Yau 3-folds
A balanced smooth rational curve in a calabi-Yau X is a smooth rational curve whose normal bundle is $O(-1)\oplus O(-1)$.
We usually like these curves because of their rigidity.
But, Is there any t …