Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with intersection-cohomology
Search options answers only
not deleted
user 519
3
votes
Accepted
Does intersection pairing on `$IH^*(X)$` agree with cup-product on `$H^*(X)$`?
I think the answer to your question is yes, at least if $X$ is irreducible.
One may think of cup product in cohomology arising from the obvious pairing in the derived category $\mathbb{Q}_{l,X} \oti …
- 10.5k