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5
votes
0
answers
302
views
Sharpness of Doob's upcrossing inequality
Provided a martingale $X$, discrete-time $X=(X_n, n\in\mathbb N)$ or continuous-time $X=(X_t, t\ge 0)$, Doob's upcrosssing inequality states that :
If $U_N(a,b)$ denotes the number of up-crossings of …
4
votes
1
answer
251
views
Explicit expression for the expected number of up-crossings of Brownian motion
Let $W$ be a standard Brownian motion starting at $1/2$, i.e. $W_0=1/2$. Set
$$\tau := \inf\big\{t>0: W_t\notin (0,1)\big\}.$$
As $(W_t^2-t)_t$ is a martingale, one has $\mathbb P[W_\tau =0]=1/2 = \ma …
3
votes
1
answer
464
views
Trajectory regularity of conditional expectation with additional randomness
Consider a probability space that support a standard Brownian motion $W=(W_t)$ and a random variable $Z$ that is independent of $W$. Denote by $\mathbb F^W=(\mathcal F^W_t)_t$ the natural filtration g …
3
votes
2
answers
238
views
Can any right-continuous martingale be approximated by continuous ones?
My questions are as follows :
Can we construct a sequence of continuous martingales $M^n=(M^n_t:0\le t\le T)$ (that can be defined in different probability spaces) such that ${\rm Law}(M^n)\to {\rm Law …
2
votes
0
answers
277
views
Identify two continuous martingales in law as time-changed Brownian motions
Let $W$ be a Brownian motion and $\alpha$ be a progressively measurable process taking values in $\mathbb R_+$. Set $\beta_t:=\max(\alpha_t, 1)$ for all $t\ge 0$. Define respectively $X$, $Y$ by
$$X_t …
2
votes
1
answer
243
views
Can we construct close martingales if their terminal marginal laws are close?
For any $\nu$ satisfying $W_2(\mu,\nu)\le \varepsilon$, can we construct two continuous martingales $X, Y$ (on suitable probability space) such that
$${\rm Law}(X)={\rm Law}(M),\quad {\rm Law}(Y_1)=\nu …
1
vote
1
answer
189
views
On a martingale defined via some SDE
Let $W$ be a one-dimensional Brownian motion. Consider the stochastic differential equation (SDE)
$$dX_t = C(t)(1-X_t)dW_t,\quad \forall t\ge 0,$$
where $C$ is a continuous and bounded function. Under …
1
vote
0
answers
125
views
Can we construct close discrete martingales if their terminal marginal laws are close?
As no answer or comment to Can we construct close martingales if their terminal marginal laws are close? … For any $\nu$ satisfying $W_2(\mu,\nu)\le \varepsilon$, can we construct two discrete-time martingales $X, Y$ (on suitable probability space) such that
$${\rm Law}(X)={\rm Law}(M),\quad {\rm Law}(Y_n)= …
1
vote
0
answers
91
views
Gluing theorem for martingales
Let $M=(M_t)_{1\le t\le 2}$ be a continuous (resp. right-continuous) martingale. Denote $x:=\mathbb E[M_1]\in\mathbb R$. Can we construct on some probability space a continuous (resp. right-continuous …
1
vote
1
answer
36
views
Uniqueness of the transport plan satisfying the super-martingale constraint
Let $\mu,\nu$ be probability measures on $\mathbb R$ such that
$$\int_{\mathbb R}|x| \mu(d x) + \int_{\mathbb R}|x| \nu(d x)<\infty.$$
$\mu\le_{cd} \nu$ is said to hold if
$$\int_{\mathbb R}(x-y)^+\mu …
0
votes
0
answers
172
views
A variant of Dubins–Schwarz's theorem
Let $W$ be a Brownian motion and $\alpha$, $\beta$ be two progressively measurable processes taking values in $\mathbb R_+$ s.t. $\alpha_t\le \beta_t$ for all $t\ge 0$. Define respectively $X$, $Y$ by …
0
votes
0
answers
21
views
Construct continuous martingales that are close to constants
Let $\mu_0,\mu_1$ be probability measures on $\mathbb R$ that are of finite second moment and increasing in convex order, i.e.
$$\int_\mathbb R f(x)\mu_0(dx) \le \int_\mathbb R f(x)\mu_1(dx)$$
holds f …
0
votes
Uniqueness of the transport plan satisfying the super-martingale constraint
The answer is non due to the very simple example. Put
$$\mu=\delta_0 \quad\mbox{and}\quad \nu=p\delta_{1}+(1-p)\delta_{-1}$$
where $p\in (0,1)$. A straightforward verification yields $\mu\le_{cd}\nu$ …
0
votes
0
answers
7
views
Characterisation of a family of continuous martingales
I look for a full characterisation of the continuous martingales $X=(X_t)_{0\leq t\leq T}$ (defined on some filtered probability space as nice as possible) such that
$$X_0=0\quad \mbox{ and } \quad\mathbb … Does this contraction contains all desired continuous martingales? …