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27 votes
2 answers
2k views

Is every commutative ring a limit of noetherian rings?

I don't care that much about Question 4, but I'm very curious about Question 5, which is Do binary coproducts always exist in the category of noetherian commutative rings? End of edit. … Is $\mathbb Z[x_1,x_2,\dots]$ a limit of noetherian rings? (The $x_i$ are indeterminates.) Question 5. Do binary coproducts exist in $\mathsf{Noeth}$? …
Pierre-Yves Gaillard's user avatar
13 votes
1 answer
465 views

Does the Cantor-Schröder-Bernstein Theorem hold in the category opposite to the category of ...

(3) If $f:A\to B$ and $g:B\to A$ are surjective morphisms of noetherian rings, are $A$ and $B$ isomorphic? The answer is Yes, because surjective endomorphisms of noetherian rings are isomorphisms. … But epimorphic endomorphisms of noetherian rings are not always isomorphisms: see this answer of Eric Wofsey. …
Pierre-Yves Gaillard's user avatar
9 votes
1 answer
818 views

Are epimorphic endomorphisms of noetherian commutative rings always injective?

Eric Wofsey gave an example of an epimorphic endomorphism of a noetherian ring which is not surjective. … (It is well known, and easy to prove, that surjective endomorphisms of noetherian rings are automatically bijective.) …
Pierre-Yves Gaillard's user avatar
2 votes
1 answer
249 views

Are unique prime ideal factorization domains locally noetherian?

. $$ Does it follow that $A$ is locally noetherian? … Here are a couple of comments: In this answer Badam Baplan pointed out that locally noetherian domains do have the indicated property, and that that some non-noetherian domains are locally noetherian
Pierre-Yves Gaillard's user avatar