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forcing, large cardinals, descriptive set theory, infinite combinatorics, cardinal characteristics, forcing axioms, ultrapowers, measures, reflection, pcf theory, models of set theory, axioms of set theory, independence, axiom of choice, continuum hypothesis, determinacy, Borel equivalence relations, Boolean-valued models, embeddings, orders, relations, transfinite recursion, set theory as a foundation of mathematics, the philosophy of set theory.

9 votes
1 answer
396 views

VC dimension of Borel sets [duplicate]

Can there be an uncountable set $S\subseteq\mathbb R$ such that for each subset $D\subseteq S$, there is a Borel set $U$ with $D=S\cap U$? I'm asking merely out of curiosity, but I'll mention that thi …
8 votes
1 answer
479 views

VC dimension of standard topology on the reals

Can there be an uncountable set $S\subseteq\mathbb R$ such that for each subset $D\subseteq S$, there is an open set $U$ with $D=S\cap U$? I'm asking merely out of curiosity, but I'll mention that thi …
5 votes
Accepted

Partitioning an infinite cardinal $\kappa$ into pairwise neighboring subsets

Yes. List the pairs $(\alpha,\beta)$ with $\alpha<\beta<\kappa$ as $(\alpha_\lambda,\beta_\lambda), \lambda<\kappa$. Then construct the sets $B_\alpha\in\mathcal B, \alpha<\kappa$ as follows: At stage …
Bjørn Kjos-Hanssen's user avatar
2 votes

Source on smooth equivalence relations under continuous reducibility?

Seems like this structure must be pretty complicated. For example, consider Brownian motion $\{W_t\}_{t\ge 0}$ with the equivalence relations $$t\sim_\omega s\iff W_t(\omega)=W_s(\omega).$$ Here $\ome …
Bjørn Kjos-Hanssen's user avatar
7 votes
Accepted

Is there a name for this equivalence relation?

$\mathscr F$-indistinguishability. In analogy with Topological indistinguishability.
Bjørn Kjos-Hanssen's user avatar
1 vote

A stronger notion of injectivity

If $A$ and $B$ are countable and equipped with probability measures $\mu_A$, $\mu_B$ that give each element positive probability then any measure-preserving map is a bijection. (I guess per @MonroeEsk …
Bjørn Kjos-Hanssen's user avatar
10 votes
Accepted

What non-standard model of arithmetic does Hofstadter reference in GEB?

My first guess is that the triples come from the fact that nonstandard countable models of PA look like $$\mathbb N + \mathbb Z\times\mathbb Q$$ and elements of $\mathbb Q$ can be represented by pairs …
Bjørn Kjos-Hanssen's user avatar
8 votes
1 answer
252 views

Automorphisms of power set lattice mod finite

Let $N$ be a countably infinite set and let $\mathcal P$ denote power set. I get that the automorphisms of $(\mathcal P(N),\subseteq)$ are all induced by permutations of $N$. But what can be said abo …
18 votes
4 answers
2k views

Complete Boolean algebra not isomorphic to a $\sigma$-algebra

Does there exist a complete Boolean algebra that is not isomorphic to any $\sigma$-algebra? If so, what is an easy or canonical example or construction?
1 vote

Choice sets in "thick" sets of sets

Let $\kappa$ be any infinite cardinal. Let $\cal S=\{\kappa\setminus\{x\}:0<x<\kappa\}$ and $C=\{0\}$. Then all the given conditions are satisfied.
Bjørn Kjos-Hanssen's user avatar
9 votes
Accepted

Choice sets from above and below

Let $\cal S=\{\{1,2\},\{2,3\},\{3,1\}\}$. Then $\cal S$ has no choice set, whatsoever. So there is no asymmetry -- not every shy set is contained in a choice set, and not every gregarious set contai …
Bjørn Kjos-Hanssen's user avatar
4 votes

Intuition for the infinite cardinals p and t (now that p = t)?

A couple of simple examples; they don't have cardinality $\mathfrak p$ or $\mathfrak t$ but depending on your knowledge they may or may not help. They are families of sets of natural numbers that I'l …
David Roberts's user avatar
  • 35.5k
1 vote
Accepted

Models of ZFC and the Borel hierarchy

@FrançoisG.Dorais commented: By reading the axioms (i.e. every axiom is satisfied, as a formalized statement) it's a $\Pi^0_{\omega+1}$ set (since satisfying a first-order sentence is $\Pi^0_n$ fo …
Bjørn Kjos-Hanssen's user avatar
19 votes
1 answer
665 views

Models of ZFC and the Borel hierarchy

The collection of binary relations $R$ on the natural numbers such that $(\mathbb{N},R) \models ZFC$ forms a Borel set, neither closed nor open -- assuming Con(ZFC). Can you show it's not $F_\sigm …
11 votes
Accepted

Usual technical term for replacing a set by the set of singletons of its members?

$A'$ is the discrete partition of $A$. That is, we think of it as a partition of $A$ induced by the finest equivalence relation, the identity relation.
Bjørn Kjos-Hanssen's user avatar

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