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1 vote

The product of two controlled operators is also a controlled operator

Indeed, I think the $E_i$'s should be $X_i$'s - I can't see what else they would be. For the last step, the implication needed is that if $x \in X_k$ and $\lambda(X_k)Tu = 0$ then $x \notin Supp(Tu)$ …
Paul Siegel's user avatar
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