Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 4213

first-order and higher-order logic, model theory, set theory, proof theory, computability theory, formal languages, definability, interplay of syntax and semantics, constructive logic, intuitionism, philosophical logic, modal logic, completeness, Gödel incompleteness, decidability, undecidability, theories of truth, truth revision, consistency.

5 votes
Accepted

Exponent function as uninterpreted function in first order logic

The function $f(m,n)=m^n$ is primitive recursive, so expressible in first-order arithmetic: there is a formula in three free variables $F(m,n,p)$ over the language of first-order arithmetic which is v …
Robin Chapman's user avatar
2 votes
Accepted

Natural number properties as uninterpreted functions in first order logic

If $f(n)$ is a predicate in the first order language of arithmetic, then "there are infinitely many $n$ such that $f(n)$ holds" can be expressed as $$\forall m\in\mathbb{N}\ \exists k\in\mathbb{N}:f(m …
Robin Chapman's user avatar
16 votes
Accepted

Order types of positive reals

Yes, one can have any countable ordering. Indeed any countable totally ordered set can be embedded in $\mathbb{Q}$. Write your ordered set as $ \lbrace a_1,a_2,\ldots \rbrace $ and define the embeddin …
Robin Chapman's user avatar
2 votes

Rank of a free module without the axiom of choice

Let $A$ and $B$ be infinite sets. Let $M$ be a rank $|B|$ module with basis $e_b$ for $b\in B$. If we take $|A|$ elements $m_a$ of $M$, then each can be expressed in terms of finitely many of the $e_b …
Robin Chapman's user avatar
10 votes

Between mu- and primitive recursion

You might look up fast-growing hierarchies.
Robin Chapman's user avatar
11 votes

How do they verify a verifier of formalized proofs?

Arguably Norman Megill's Metamath http://metamath.org/ is not a mainstream proof verifier. But various third parties have written short programs to check his deductions, starting with Ralph Lieven's m …
Robin Chapman's user avatar