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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.

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Does the functor $\mathcal{C} \to \mathcal{Z}(\mathcal{C})$ have adjoints?

Short answer: Yes, it can possibly have an adjoint. Longer answer: Assume that $\mathcal{C}$ is rigid, and that the coend $L = \int^{X \in \mathcal{C}} X^* \otimes X$ exists. It is a coalgebra. Your a …
Jo Mo's user avatar
  • 338
1 vote
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Reference for "adjunction up to twisting by autoequivalences"

Does anyone have any references on the following type of thing, which one might call "adjunction up to autoequivalences"? We have functors $F \colon C \to D$ and $F' \colon D \to C$, but they are not …
Jo Mo's user avatar
  • 338