Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with gt.geometric-topology
Search options not deleted
user 4008
Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).
7
votes
Is the composition of two bundle projections necessarily a bundle projection?
I think that the following works: Let $X\to Y$ and $Y\to Z$ be locally trivial
fibrations with all spaces paracompact and $Z$ locally contractible (I do not assume that a
fibration implies that all fi …
- 22.6k
5
votes
Accepted
composition of covering map and bundle projection
It is better to just assume that $f$ is a covering space. By shrinking $Z$ we may assume that that $Z$ is a ball and that $Y=Z\times F$. As $X\to Y$ is a covering space and $Z$ is simply-connected the …
- 22.6k
22
votes
"Largest" finite-dimensional Lie subgroups of Diff(S^n), are they known?
For 2) I think the following is an answer: Suppose $K$ is a compact Lie subgroup
of $\mathrm{Diff}(S^n)$ of dimension $\geq{n+1\choose 2}$. Being compact it is
the group of isometries of some Riemanni …
- 22.6k