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Stable homotopy theory is that part of homotopy theory (and thus algebraic topology) concerned with all structure and phenomena that remain after sufficiently many applications of the suspension functor.
22
votes
Accepted
Is $[X, \_]$ a homology theory?
This holds only for compact objects (i.e. finite CW spectra), since it is easy to see that additivity fails otherwise (the other axioms of homology theories are satisfied). The usual way to obtain a h …
16
votes
What is the first interesting matric Toda bracket in the stable homotopy of the sphere?
I know this post is quite old, but in case you are still interested, or anyone else is, I thought about sharing my recent thoughts about the topic. After all, this is the second result on "matric toda …
14
votes
Accepted
Why are ordinary spheres not strictly invertible?
An $E_{\infty}$ structure extending the $E_1$ structure on $R(n)$ in particular yields maps $(\mathbb{S}^{2n})^{\otimes p}_{hC_p} \to \mathbb{S}^{2pn}$ splitting the inclusion of the bottom cell. The …
13
votes
Accepted
Does there exist a Bousfield localization of the category of spectra which makes the sphere ...
EDIT: I'll leave the old answer up, see below. In the meantime, Maxime Ramzi and I have thought this through and came up with a fun general argument.
Claim. Let $L: \mathrm{Sp}\to \mathrm{Sp}$ be a Bo …
12
votes
Accepted
Why isn't the anchor map in Lurie's "Rotation Invariance in Algebraic K-Theory" zero?
It's zero as a map of filtered spectra, but it is considered as a map of $\mathbb{A}$-bimodules.
7
votes
Accepted
Does the homotopy category of finite spectra act on stable homotopy categories?
Yes: Since $\mathcal{C}$ is stable, $\operatorname{Fun}(\mathcal{C},\mathcal{C})$ is stable, too. In particular, it has finite colimits, so $\operatorname{Ind}\operatorname{Fun}(\mathcal{C},\mathcal{C …
7
votes
Accepted
Proof of the equivalence of spectra $(\mathbb{S}^{-1} \otimes \mathbb{S}^{-1})_{h \Sigma_2} ...
This is probably not quite what you were looking for, but since you said you'd also be happy to see any proof, here is one using a modern perspective on Thom spectra of virtual bundles:
The flip actio …
7
votes
Accepted
Infinite suspension is cotangent complex
It is not, for example note that if this were true, the case $A=B$ would give you that $L_{B/B}$ is the infinite suspension of $\mathrm{id}: B\to B$. But that's the absolute cotangent complex $L_B$, w …
6
votes
Accepted
Filtered homotopy colimits of spectra
This is a partial answer, not addressing the relation to homotopy colimits in a model category presenting $\mathcal{C}$ (but I think there should be some reasonable statement there, the slogan is cert …
5
votes
Accepted
Reference for the equivalence between chain complexes and sequential diagrams in a stable $\...
I believe https://arxiv.org/abs/2109.01017 does what you want! The description of coherent chain complexes used there is a bit different than what you suggest, but they look equivalent at first glance …