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rigid analytic varieties, affinoid varieties, strictly convergent power series over non-archimedean fields

7 votes
1 answer
493 views

Are admissible open subsets of an affinoid space of countable type?

A rigid analytic space $Y$ over a complete non-archimedean valued field $k$ is said to be of countable type if it has a countable (possibly finite) admissible covering by affinoids over $k$. Suppos …
Simon Wadsley's user avatar
16 votes

D-modules on rigid analytic spaces

Yes. Although it is only beginning to be developed. You probably want to start with Berthelot: D-modules arithmétiques I : Opérateurs différentiels de niveau fini and Introduction à la théorie arithm …
Simon Wadsley's user avatar
1 vote
1 answer
755 views

What are in units of an affinoid algebra?

Suppose that $K$ is a complete local field and $A$ is an affinoid $K$-algebra. Is there a known way to produce an explicit description of the units of $A$? Here is what I already know: write $A^\circ …
Simon Wadsley's user avatar
9 votes
1 answer
1k views

Reference Request: Vector bundles in rigid analytic geometry

In algebraic geometry it is well-known (see Hartshorne Exercise II.5.16 for example) that there is a 1-1 correspondence between rank $n$ (geometric) vector bundles $\pi\colon Y\to X$ on a scheme $X$ a …
Simon Wadsley's user avatar
4 votes
Accepted

What's the relation between pseudo-compact and admissible rings?

Neither of these properties implies the other: There is an admissible algebra that is not pseudo-compact If $A$ is a ring with the discrete topology that is not artinian then it is admissible but not …
Simon Wadsley's user avatar