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Homotopy theory, homological algebra, algebraic treatments of manifolds.
3
votes
Continuous surjection $S^n\to S^m$, $n<m$
$S^1$ can be projected on $I$. and there is a continuous surjection from $I^2$ to $S^2$ : for example, start with $I^2$ glue together two opposite edge, you get a cylinder. Then collapse on two points …
8
votes
Accepted
Is the suspension of a finite fibration again finite?
Assuming you work with unpointed spaces (but the example can easily be adapted to the pointed case) the map $1 \to 2$ gives a counterexample : its fiber are $1$ and $\varnothing$ so they are both fini …
8
votes
1
answer
468
views
A model structure on semi-simplicial algebraic Kan complexes?
By an algebraic semi-simplicial kan complex I mean a semi-simplicial set (i.e. a presheaf on the category of finite ordered sets and injective order preserving maps), which is a Kan complex (in the se …
3
votes
A model structure on semi-simplicial algebraic Kan complexes?
I went back to this question a few days ago and found the solution: it is indeed a true model structure.
I have two (related) approaches to this, but anyway the key point is the semi-simplicial appro …
17
votes
1
answer
761
views
Idempotent ring spectrum
Is there a lot of ring spectrum which are idempotent in the sense that the multiplication map $R \wedge R \rightarrow R$ is an equivalence ?
The sphere spectrum $\mathbb{S}$ and the $0$ spectrum are …
8
votes
2
answers
329
views
example of "really" non-existent transferred model structure
I am looking for an example where a transferred model structure fails to exist, even if one is willing to work with semi-model category. But let me be more precise:
Let's say I have a combinatorial mo …
9
votes
Accepted
Interpretation of the monomorphism $H^2(\pi_1(X),\mathbb{Z}) \rightarrow H^2(X,\mathbb{Z})$
First, let's see what is this map $H^2(\pi_1(X),A) \rightarrow H^2(X,A)$.
$\pi_1(X)$ is characterized by the following property: A set endowed with a left action of $\pi_1(X)$ is the same thing as a …
7
votes
Accepted
Groupoids as models of symmetric simplicial sets
You can definitely characterize groupoids as presheaves on $Fin_+$ preserving some colimtis (i.e. sending some colimits in $Fin_+$ to limits in Set). In fact Groupoids are the presheaf on $Fin_+$ that …
3
votes
Accepted
Euclidean model structure on multipointed $d$-spaces
As mentioned by David White in the comment, I've recently proved that left induced model structure exists (without any kind of large cardinal axiom) for any "tractable" class of cofibrations on a loc …
3
votes
1
answer
244
views
Isomorphism class of locally trivial object classified by some $H^1$ ?
Hello,
I have noticed some fact about cohomologie : when i have some kind of strucutre in a topos (for example the $G$-object for $G$ a group object in the topos) and a particular object $X$ model of …
15
votes
2
answers
940
views
Are strict $\infty$-categories localized at weak equivalences a full subcategory of weak $\i...
One has a nice "folk" model structure on strict $\infty$-categories due to Yves Lafont, Francois Metayer and Krzysztof Worytkiewicz whose notion of weak equivalences seem to be the notion of weak equi …
14
votes
1
answer
294
views
Detecting weak equivalence on free loop space homology
Given $f:X \to Y$ a continuous map between two spaces (unpointed CW-complexes) such that $f$ induces an isomorphism in homology with integer coefficient, and $f$ induces an isomorphism on homology of …
13
votes
0
answers
477
views
Examples of non-proper model structure
I have recently been thinking about left and right semi-model categories and in which case they can be promoted to Quillen model structure, and I have come to the conclusion that that absolutely all t …
15
votes
1
answer
494
views
On diagrams in model categories and rectification
For a model category $C$, I'm denoting $h_\infty(C)$ the associated $\infty$-category (for example its Dwyer-Kan localization at weak equivalences, or if $C$ is simplicial the simplicial nerve of the …
47
votes
What is the mistake in the proof of the Homotopy hypothesis by Kapranov and Voevodsky?
It's been more than a year and a half since I asked this question and I had a lot of thought about it so I decided I will post my own answer.
First I entirely agree with Yonatan that the main problem …