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4 votes

What are the known implications of "There exists a Reinhardt cardinal" in the theory "ZF + j"?

First, let's show that I-1 implies I0: Suppose $I-1(\kappa,\delta, j)$; we may assume, by forcing if necessary, that $V_\kappa$ (and hence $V_\delta$) satisfies the Axiom of Choice. Now if j is a ran …
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