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Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

10 votes
Accepted

Isometries between spherical space forms

Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G. Complexes à automorphismes et homéomorphie différentiable. Ann. Inst. Fourie …
Igor Belegradek's user avatar
9 votes

When a compact topological manifold with boundary is a ball?

I wish to address the case $n=4$. This would follow if any $4$-dimensional h-cobordism between $3$-spheres were trivial but at the moment I am not sure how to prove this. There is however a different …
Igor Belegradek's user avatar
15 votes

exotic differentiable structures on manifolds in dimensions 5 and 6

Any PL-manifold of dimension $\le 7$ is smoothable, and the smooth structure is unique in dimensions $5,6$. See e.g. remark 6.7 in Rudyak's paper for details. EDIT: To explain the above, the smooth …
Igor Belegradek's user avatar
43 votes
Accepted

Examples of non-diffeomorphic smooth manifolds with diffeomorphic tangent bundle

Here are examples of non-diffeomorphic closed manifolds with diffeomorphic tangent bundles: 3-dimensional lens spaces have trivial tangent bundles, which are diffeomorphic if and only if the lens sp …
Igor Belegradek's user avatar
16 votes

the criteria for 3-dim manifolds diffeomorphic to $\mathbb{R}^3$

I am not sure what Schoen and Yau had in mind. Any open contractible $n$-manifold that is simply-connected at infinity is homeomorphic to $\mathbb R^n$. This is due to Stallings [1] if $n\ge 5$ and to …
Igor Belegradek's user avatar
35 votes
Accepted

If a manifold suspends to a sphere...

Suppose $M$ is a closed $n$-manifold whose suspension is homeomorphic to $S^{n+1}$. Removing the two "singular" points from the suspension gives $M\times \mathbb R$, while removing two points from $S^ …
Igor Belegradek's user avatar
13 votes
Accepted

4-dimensional h-cobordisms

I think both questions are open. The somewhat sad state of affairs is that there are nontrivial TOP 4d s-cobordisms that are either nonsmoothable or not known to be smoothable, and there are smooth 4d …
Igor Belegradek's user avatar
3 votes

PL-embeddings of balls into PL-manifolds

The precise result you want is Theorem 4.20 (page 56) in Rourke-Sanderson's book. The notations in the statement are on page 50, but they are self-explanatory, e.g., $I^{n,q}$ is the standard disk pa …
Igor Belegradek's user avatar
17 votes

Simply-connected rational homology spheres

A complete answer can be found in a paper by D. Ruberman Null-homotopic embedded spheres of codimension one: a simply-connected rational homology $n$-sphere that is not homeomorphic to $S^n$ exists if …
Igor Belegradek's user avatar
8 votes
Accepted

Subgroups of Gromov's hyperbolic groups

The answer is no. The case when $H$ isn't finitely generated is trivial (think of the free groups and its commutator subgroup), examples when $H$ is finitely generated are due to Rips (see the famous …
Igor Belegradek's user avatar
14 votes

circle action on sphere

Classification of circle actions on (standard and on exotic) spheres is a classical activity in transformation groups, see e.g. the article of Schultz in the collection "Group actions on manifolds", p …
Igor Belegradek's user avatar
1 vote

homotopy type of complement of subspace arrangement

Since you arrangement is so simple, there are must be some purely topological methods to check asphericity (or non-asphericity) of its complement. This is a well-developed subject I do not know much a …
Igor Belegradek's user avatar
7 votes

Are there unique geodesics in the NIL and SOL geometry?

Despite their non-uniqueness, a lot is known about geodesics of left-invariant metrics on Heisenberg groups. For example, Jang-Park [Conjugate points on 2-step nilpotent groups, Geom. Dedicata 79 (200 …
Igor Belegradek's user avatar
2 votes

Existence of sequence of examples of braking 'Cancellation law in homeomorphic products'

Take any closed $4$-manifold with infinitely many smooth structures, and multiply it by a torus. The product has only finitely many smooth structures, in fact any manifold $M$ of dimension $\ge 5$ ha …
Igor Belegradek's user avatar
9 votes

Is every connected metrizable locally path connected space a length space?

This is not an answer but a long comment with references for the locally compact case. It is proved in [Tominaga-Tanaka, Convexification of locally connected generalized continua. J. Sci. Hiroshima Un …
Igor Belegradek's user avatar

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