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1 vote

Do singular fibers determine the elliptic K3 surface, generically?

Edit notice: As Evgeny Shinder pointed out in the comment, it is unclear why we have $S = J^{-1}(\{0,1,\infty\})$ where $J : C \to \mathbf{P}^1$ is the $j$-invariant map. The problem is that $X \to S$ …
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