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4
votes
Neighborhood theorem for conical Lagrangian
The answer is 'no', even in the simplest nontrivial case $n=2$, if you assume that the symplectomorphism is to take $C$ to $C'$. (If you don't assume that the symplectomorphism is supposed to take $C …
5
votes
How to find equations of a sub-Riemannian problem
There are a number of sources. If you are comfortable using differential forms, then one source that you may find useful is
L. Hsu, Calculus of variations via the Griffiths formalism, J. Differential …
7
votes
Accepted
How many Lagrangian submanifolds?
The answer to the first question is 'no'. For example, if $M = S^2\times S^2$ is given the product symplectic structure, then there is no Lagrangian submanifold in the homology class of $S^2\times\{x …