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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.

4 votes

How to prove that there are no exponential object in a category?

As a first step, it may help to choose some relatively simple examples of $X$ and $Y$. If you can find a characterization of objects in your category as representable presheaves among all presheaves, …
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4 votes

Are there examples where one proves something about the functor represented by an object usi...

An absolute Galois group is an inverse limit of finite Galois groups over a system of finite Galois extensions of fields, so it represents a functor on groups defined by a compatible system of homomor …
5 votes
Accepted

Finiteness and cardinality in abstract categories

If your category has a monoidal structure, you can ask for an object to be dualizable. This is a generalization of finite-dimensionality for vector spaces.
S. Carnahan's user avatar
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4 votes

Quotient of a category by a free group action

The answer is yes, provided your action has the following data that you didn't specify: For any g in G and any f: a -> b, an assignment gf: ga -> gb, in a way that strictly respects multiplication i …
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2 votes

Candidate definitions for "1-braided 2-category"?

As you mentioned, the commutor doesn't generally make sense if your 2-category has morphisms between distinct objects. Therefore, here's a first try at a definition: a collection of braided monoidal …
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3 votes

Is there a "groupoid integral" with values in a groupoid?

Yes. It seems you're only looking for an object up to isomorphism, so all you really need is divisibility and addition to yield objects that are well-defined up to isomorphism. Assuming your notion …
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2 votes

The condition End(1) = k in Tannakian Categories

Assuming you have such an equivalence of categories, the object $1$ is sent to the trivial representation of your affine $k$-group $G$. This is the representation that factors through the canonical h …
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7 votes
Accepted

What about the empty torsor?

If you have any category that admits finite products, you have a notion of $G$-pseudotorsor, namely an object $X$ equipped with a map $act: G \times X \to X$, such that $act \circ (id_G, act) = act …
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3 votes
Accepted

(Sh,Sh-map) represents the category of sheaves on a stack.

The notes you are reading seem to disagree with more commonly accepted language (cf. SGA1 Exp 13, Vistoli's notes, or the Stacks project). Some of this seems to be an attempt at expository ease, e.g. …
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1 vote

What is the "right" definition of the free abelian group on a set?

You might not find this satisfying, but I think the standard description $\displaystyle{\bigoplus_{s \in S} \mathbb{Z} e_s}$ not only makes the adjunction clear on the level of objects, but also makes …
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4 votes

Example of a commutative algebra object in a braded monoidal category C

The group ring of any group $G$ yields a special case of Noah's answer, where $C$ is the monoidal category of $G$-graded vector spaces. I wrote this up in a blog post a few years ago.
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5 votes
Accepted

Categories internal to schemes and subschemes of invertible arrows

The answer to your question is "yes". We need the following properties of $X_1^{iso}$: The map $X_1^{iso} \to X_1$ given by $(f,g) \mapsto f$ on scheme-valued points is a monomorphism. This is str …
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9 votes
Accepted

Nerves of (braided or symmetric) monoidal categories

If you want to capture the structure of the category together with its monoidal structure, you may need a $k$-fold simplicial set for $k>1$, i.e., a functor from $(\Delta^{op})^k$ to sets. One of the …
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6 votes
Accepted

Reference request for category theory works which quickly prove the theorem which generalise...

If you want a categorical proof that encompasses nonabelian groups and rings-without-identity, then you need to work with concepts such as "normal subobject" that are (I think) not really part of the …
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9 votes

Definition of the symmetric algebra in arbitrary characteristic for graded vector spaces

Symmetric algebras (aka free commutative associative unital algebras) are given by a functor, and they satisfy a universal property: If M is a module over a commutative ring k and R is a commutative k …
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