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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.
4
votes
How to prove that there are no exponential object in a category?
As a first step, it may help to choose some relatively simple examples of $X$ and $Y$. If you can find a characterization of objects in your category as representable presheaves among all presheaves, …
4
votes
Are there examples where one proves something about the functor represented by an object usi...
An absolute Galois group is an inverse limit of finite Galois groups over a system of finite Galois extensions of fields, so it represents a functor on groups defined by a compatible system of homomor …
5
votes
Accepted
Finiteness and cardinality in abstract categories
If your category has a monoidal structure, you can ask for an object to be dualizable. This is a generalization of finite-dimensionality for vector spaces.
4
votes
Quotient of a category by a free group action
The answer is yes, provided your action has the following data that you didn't specify:
For any g in G and any f: a -> b, an assignment gf: ga -> gb, in a way that strictly respects multiplication i …
2
votes
Candidate definitions for "1-braided 2-category"?
As you mentioned, the commutor doesn't generally make sense if your 2-category has morphisms between distinct objects. Therefore, here's a first try at a definition: a collection of braided monoidal …
3
votes
Is there a "groupoid integral" with values in a groupoid?
Yes. It seems you're only looking for an object up to isomorphism, so all you really need is divisibility and addition to yield objects that are well-defined up to isomorphism. Assuming your notion …
2
votes
The condition End(1) = k in Tannakian Categories
Assuming you have such an equivalence of categories, the object $1$ is sent to the trivial representation of your affine $k$-group $G$. This is the representation that factors through the canonical h …
7
votes
Accepted
What about the empty torsor?
If you have any category that admits finite products, you have a notion of $G$-pseudotorsor, namely an object $X$ equipped with a map $act: G \times X \to X$, such that
$act \circ (id_G, act) = act …
3
votes
Accepted
(Sh,Sh-map) represents the category of sheaves on a stack.
The notes you are reading seem to disagree with more commonly accepted language (cf. SGA1 Exp 13, Vistoli's notes, or the Stacks project). Some of this seems to be an attempt at expository ease, e.g. …
1
vote
What is the "right" definition of the free abelian group on a set?
You might not find this satisfying, but I think the standard description $\displaystyle{\bigoplus_{s \in S} \mathbb{Z} e_s}$ not only makes the adjunction clear on the level of objects, but also makes …
4
votes
Example of a commutative algebra object in a braded monoidal category C
The group ring of any group $G$ yields a special case of Noah's answer, where $C$ is the monoidal category of $G$-graded vector spaces. I wrote this up in a blog post a few years ago.
5
votes
Accepted
Categories internal to schemes and subschemes of invertible arrows
The answer to your question is "yes". We need the following properties of $X_1^{iso}$:
The map $X_1^{iso} \to X_1$ given by $(f,g) \mapsto f$ on scheme-valued points is a monomorphism. This is str …
9
votes
Accepted
Nerves of (braided or symmetric) monoidal categories
If you want to capture the structure of the category together with its monoidal structure, you may need a $k$-fold simplicial set for $k>1$, i.e., a functor from $(\Delta^{op})^k$ to sets. One of the …
6
votes
Accepted
Reference request for category theory works which quickly prove the theorem which generalise...
If you want a categorical proof that encompasses nonabelian groups and rings-without-identity, then you need to work with concepts such as "normal subobject" that are (I think) not really part of the …
9
votes
Definition of the symmetric algebra in arbitrary characteristic for graded vector spaces
Symmetric algebras (aka free commutative associative unital algebras) are given by a functor, and they satisfy a universal property: If M is a module over a commutative ring k and R is a commutative k …