Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 10366

Algebraic and topological K-theory, relations with topology, commutative algebra, and operator algebras

3 votes

$K$-homology of $BG$

For finite-type torsion spectra $X$ there is a natural isomorphism $$ KU_{n-1}(X) \simeq \text{Hom}_c(KU^n(X),\mathbb{Q}/\mathbb{Z}). $$ Here $\text{Hom}_c$ denotes the group of homomorphisms that ar …
Neil Strickland's user avatar
17 votes
Accepted

Mayer-Vietoris sequence for topological K-theory

Freed, Hopkins and Teleman will be using the homotopical definition $K^0(X)=[X,\mathbb{Z}\times BU]$. For many spaces $X$ this is the same as the Grothendieck group of vector bundles on $X$; in parti …
Neil Strickland's user avatar
8 votes
Accepted

K-groups of a permutative category - are they finite?

First, I do not think that strict associativity makes a difference, so I will ignore it. Next, let $G$ be a finite group, and let $\mathcal{C}G$ be the category of finite $G$-sets and equivariant bij …
Neil Strickland's user avatar
3 votes
Accepted

Are these vector bundles, trivial bundle?

There is an evident map $\mathbb{R}P^{m-1}\times\mathbb{R}P^{n-1}\to PX$, which is easily seen to be an isomorphism. (This is called the Segre embedding.) If we pull back the tautological bundle of …
Neil Strickland's user avatar
5 votes
Accepted

What is the group of additive operations on topological K-theory?

The most explicit answers are in work of Sarah Whitehouse and her collaborators. You could start with this paper and its references: http://www.ams.org/journals/proc/2010-138-06/S0002-9939-10-10237- …
Neil Strickland's user avatar
13 votes
Accepted

Which spaces have trivial K-theory?

I'll just give an answer for finite complexes $X$. The condition $\widetilde{K}^*(X)=0$ only depends on the suspension spectrum of $X$ so this is naturally regarded as a question in stable homotopy th …
Neil Strickland's user avatar
3 votes

H-space structures on non-sphere suspensions?

Here are some comments about the case where $X$ is not assumed to have finite type. Put $Y=\Sigma X$. For any field $K$, the groups $H_*(Y;K)$ form a Hopf algebra in which all elements of the augmen …
Neil Strickland's user avatar
8 votes
Accepted

Properties of coefficients of ring spectra

You have given yourself an invertible element $u\in\pi_2(R)$ and a coordinate $x\in R^2(\mathbb{C}P^\infty)$ with $\psi(x)=x\otimes 1 + 1\otimes x + ux\otimes x$. This means that the class $m=1+ux\in …
Neil Strickland's user avatar
13 votes
Accepted

Trivial cobordism group in dimensions 1, 3, 7 related to H-space structures on the spheres i...

The cobordism groups can be calculated using the Adams spectral sequence, which is based on the homological algebra of modules over the Steenrod algebra. This works most nicely for the unoriented cob …
Neil Strickland's user avatar
5 votes

Maps from mod-$p$ Eilenberg-MacLane spectrum to connective $K$-theory spectrum

There are cofibrations $$\Sigma^2 kU\xrightarrow{v} kU\to H\xrightarrow{\alpha}\Sigma^3 kU$$ and $$ H\xrightarrow{p}H\to H/p\xrightarrow{\beta} \Sigma H. $$ The composite $\alpha\beta\colon H/p\to\ …
Neil Strickland's user avatar
5 votes
Accepted

Cohomology theory with only one Adams operation?

Adams operations exist in quite wide generality. For any even periodic ring spectra $E$ and $F$, we have associated formal groups $G_E$ and $G_F$ over base schemes $S_E$ and $S_F$. There is a moduli …
Neil Strickland's user avatar
4 votes

Computation of cohomology of Morava $K$-Theory

Depending on exactly what you are trying to do, you may find it more useful to consider $E^0(BV)$, where $E$ is Morava $E$-theory and $V\simeq(\mathbb{Z}/p)^d$. (Here everything is $2$-periodic and co …
Neil Strickland's user avatar
8 votes
Accepted

Is $KU\otimes S^1_+$ isomorphic to $F(S^1_+,KU)$ as $E_\infty$ rings?

This seems to be an answer, based on discussion with Maxime Ramzi in the comments. The space of $E_\infty$ $KU$-algebra maps from $KU\otimes S^1_+\to F(S^1_+,KU)$ is the same as the space of $E_\infty …
Neil Strickland's user avatar
16 votes

"a sign that one should be computing K-theory"

Usually you are computing $H^*(X)$ or $K^*(X)$ for a reason; for example if $H^*(X)\not\simeq H^*(Y)$ then you know that $X$ and $Y$ are not homotopy equivalent, but if $H^*(X)\simeq H^*(Y)$ and this …
Neil Strickland's user avatar
6 votes
Accepted

(Geometric) Proof for the projective bundle formula in K-theory

First, for any bundle $V$ of dimension $d$ over $Y$ put $$ \lambda(V)(t) = \sum (-1)^k[\Lambda^k(V)]t^{d-k} \in K^0(Y)[t]. $$ This is a monic polynomial of degree $d$ over $K^0(Y)$. It satisfies $\l …
Neil Strickland's user avatar

15 30 50 per page