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Bob
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The center of Sylow subgroups

Let $P\in Syl_{p}(\Phi(G))$,where $p\in \pi(\Phi(G))$. $\Phi(G)$ is the Frattini subgroup of $G$, $\pi(\Phi(G))$ is the set of prime divisors of $|\Phi(G)|$.Suppose every subgroup $H$ of $P$ of order $p$ is normal in $G$.Let $P_1\in Syl_{p}(G)$,we can use $|H|=p$ and $H$ is normal in $G$ to prove that $H\leq P_1$.Then can we prove $H\leq Z(P_1)$?

Bob
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