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A.Skutin
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Is $X$ closed in $Aut_{\mathbb{C}(t)}(\mathbb{C}(t)[x_1,\ldots, x_n])$?

Consider $\mathbb{C}$-algebras

$$A = \mathbb{C}[t][x_1,\ldots, x_n]\subset\mathbb{C}(t)[x_1,\ldots, x_n] = B$$

Group $\operatorname{Aut}_{k(t)}(k(t)[x_1,\ldots, x_n])$ carry a power series topology (see https://arxiv.org/abs/1712.01490 p.2).

Fix $f\in B$. Is it true that $X =\{\pi\in\operatorname{Aut}_{\mathbb{C}(t)}(\mathbb{C}(t)[x_1,\ldots, x_n])|\pi(f)\in A\}$ is closed in $\operatorname{Aut}_{\mathbb{C}(t)}(\mathbb{C}(t)[x_1,\ldots, x_n])$ with respect to power series topology?

In fact, for my research it is more interesting to answer the following question

$$\mathcal{A} = \text{Der}_{\mathbb{C}[t]}(A) = A\partial_{x_1}\oplus\ldots\oplus A\partial_{x_n}\subset B\partial_{x_1}\oplus\ldots\oplus B\partial_{x_n} = \text{Der}_{\mathbb{C}(t)}(B) = \mathcal{B}$$

Fix $\partial\in\mathcal{B}$. Is it true that $\textbf{X} = \{\pi\in\text{Aut}_{\mathbb{C}(t)}(\mathbb{C}(t)[x_1,\ldots, x_n])|\pi(\partial)\in\mathcal{A}\}$ is closed in $\text{Aut}_{\mathbb{C}(t)}(\mathbb{C}(t)[x_1,\ldots, x_n])$ with respect to power series topology?

A.Skutin
  • 329
  • 2
  • 13