I am learning Cartan's moving frame from chapter 6 of S.S. Chern's book "Lectures on differential geometry" (Google books). Suppose the moving frame in $E^N$ is denoted by $(p;e_1,\cdots,e_N)$, then we can apply an infinitesimal motion on $(p;e_1,\cdots,e_N)$ to get the equation (3.22) on p.202 Chern's book:
\begin{equation} \left\{ \begin{split} dp=\displaystyle{\sum_{\alpha=1}^{N}\omega^{\alpha}e_{\alpha}}\\ de_{\alpha}=\displaystyle{\sum_{\beta=1}^{N}\omega^{\beta}_{\alpha}e_{\beta}} \end{split} \right. \end{equation} where the $\omega^{\alpha}$ and $\omega^{\beta}_{\alpha}$ are one forms. In my understanding, the $e_{\alpha}$'s are understood as $\mathbb{R}^N$ valued functions (of some $N$ variables $(u_1,\cdots,u_N)$) since we can do the operator $d$ to them. In other words, the $e_{\alpha}$'s are not really vector fields in $\mathbb{R}^N$ (by vector field I mean a contravariant 1-tensor field) since we can't do the $d$ operator to a vector field. However, Chern's book treat the $e_{\alpha}$'s as vector fields and it takes the one forms $\omega^{\beta}_{\alpha}$ as connection 1-form as the Levi-Civita connection for $\mathbb{R}^N$ and do covariant derivative $D$ to $e_{\alpha}$ (this is (3.38) on p.207 Chern's book): $$ De_{\alpha}=\omega_{\alpha}^{\beta}e_{\beta} $$ (Here, I take $m=N$ in Chern's book). So my question is why we can treat the $e_{\alpha}$ as contravariant fileds in $\mathbb{R}^N$ and do the $d$ operator to them? Why the one forms $\omega_{\alpha}^{\beta}$ (gotten from the equation for the moving frame) are exactly the connection 1-forms for the Levi-Civita connection on $\mathbb{R}^N$?