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Moving from $\Re(s) = 1+\epsilon$ to $\Re(s) = \frac{1}{2}$ in the proof of the Weil-Guinand explicit formula

In all proofs of the Weil-Guinand explicit formula, there's this step (this is from Paul Garrett's notes):

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Now consider this:

(1) $\frac{\zeta^\prime(s)}{\zeta(s)}$ has poles at $s=1$ and $s=\frac{1}{2} + i \gamma$, so if we move the contour from $\Re(s) = 1+\epsilon$, to $\Re(s) = \frac{1}{2}$, we'll pick up all the residues.

(2) Yet if we write out the Dirichlet series of $\frac{\zeta^\prime(s)}{\zeta(s)}$, then $p^{-ms}$ has no pole between $\Re(s) = 1+\epsilon$ and $\Re(s) = \frac{1}{2}$, so the proof claim we can move the contour to $\Re(s) = \frac{1}{2}$ without picking up any residues. Is this really justified?

So the question is: does moving the contour involve any residues? (1) says yes. (2) says no. This is strange.