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alvarezpaiva
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Averaging lengths and distances

A natural way in which Finsler metrics appear in Riemannian geometry is as averages of Riemannian metrics (e.g., the average of the arc-length elements $\sqrt{dx^2 + dy^2}$ and $\sqrt{2dx^2 + 3dy^2}$ is not the arc-length element of a Riemannian metric on the plane). A simple application of this idea is the construction of a class of (Finsler) metrics in projective space for which geodesics are projective lines:

Consider the group $G$ of projective transformations on projective $n$-space and let $\mu$ be a compactly-supported Borel probability measure on $G$. Define the length of a curve $\gamma$ to be the expected value of the (canonical) length of the curve $T(\gamma)$, where $T \in G$.

Claim. The preceding construction defines a length structure on $\mathbb{R}P^n$ for which projective lines are geodesics.

This is essentially the same construction as in this MO question.

We can consider the following abstract version of this construction:

Consider a length space $(X,d)$ and a continuous group action $G \times X \rightarrow X$ of a locally compact topological group $G$ on the space $X$. If $\mu$ is a compactly-supported Borel probability measure on $G$, define the length of a curve $\gamma$ to be the expected value of the (canonical) $\mu$-length of the curve $T(\gamma)$, where $T \in G$, and define the $\mu$-distance between two points $x, y \in X$ as the expected value of $T \mapsto d(Tx,Ty)$.

Questions.

1. Is the length of a curve in $(X,d_\mu)$ equal to its $\mu$-length?

2. Is $(X,d_\mu)$ a length space?

3. If $(X,d)$ is a Riemannian torus with distance function $d$, $G$ is also the torus acting on itself by translations, and $\mu$ is the normalized Haar measure on $G$, is it true that $d_\mu$ the flat metric induced by the stable norm?

Let me sketch why I think this last question may have a positive answer: a characterization of the stable norm by D. Burago states that if $d$ is a periodic metric (the lift to $\mathbb{R}^n$ of a length metric on $\mathbb{R}^n/\mathbb{Z}^n$), the stable norm is the unique norm satisfying $$ \|x-y\| - C \leq d(x,y) \leq \|x-y\| + C $$ for some constant $C > 0$ independent of $x$ and $y$. I hadn't noticed this before, but this means that the set of periodic metrics sharing the same stable norm is a convex set and, therefore, an average of periodic metrics with the same stable norm $\|\cdot\|$ (if it is a length metric) will yield a periodic metric with stable norm $\|\cdot\|$. Averaging the metrics $d(x+z,y+z)$ as $z$ ranges over all points in the unit square should then yield a translation-invariant metric whose stable norm is $\|\cdot\|$. With some luck, this translation-invariant metric is induced by a norm and by Burago's theorem it would have to be the stable norm.

Disclaimer. I really haven't thought all these things through, but I thought it would be helpful to write it down to make things clearer (at least for myself) and perhaps someone here has already considered these averages. They are quite natural.

alvarezpaiva
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