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13 votes
0 answers
355 views

Analog of Haar element in an algebra

In a Hopf algebra $H $ (over some field $ k $), there is the notion of a Haar element $ h \in H$. This is an element of the algebra which has the property that if $ V $ is a representation of $ H $, ...
Joel Kamnitzer's user avatar
12 votes
0 answers
605 views

Given an algebra, can it be realized as a block of a Hopf algebra?

During a classification problem I came across a set of algebras given as the path algebra of a quiver with relations. As an example the local ones: $k\langle x,y\rangle/x^2,y^2, xy-qyx$, where $q\in k$...
Julian Kuelshammer's user avatar
10 votes
0 answers
275 views

Are local finite dimensional Hopf algebras symmetric?

Recall that a finite dimensional algebra $A$ over a field $K$is called a Frobenius algebra in case $A \cong D(A)$ as right modules, where $D(A) \cong Hom_K(A,K)$. In case $A \cong D(A)$ as bimodules, ...
Mare's user avatar
  • 26.5k
6 votes
2 answers
375 views

Is the Cartan matrix of a finite-dimensional (Hopf) algebra invertible over the rationals?

This is probably well-known to representation theorists, but this doesn't imply being well-known to me. Let $k$ be a field, and let $A$ be a $k$-algebra that is finite-dimensional as a $k$-vector ...
darij grinberg's user avatar
5 votes
2 answers
680 views

Characters on Hopf algebras

For any algebra $A$, a character for $A$ is a non-zero algebra map $c:A \to \mathbb{C}$. For $H$ be a Hopf algebra, a character is given by $\epsilon:H \to \mathbb{C}$ the counit of $H$. I am looking ...
Fofi Konstantopoulou's user avatar
5 votes
2 answers
384 views

a question about finite dimensional representation of a Hopf algebra

Let $H$ be a Hopf algebra over a field $k$ and $V$ a finite dimensional left $H$-module. Then $End_{k}(V)$ is a right $H$-module via $(f\cdot h)(v)=S(h_{1})f(h_{2}\cdot v)$. We set $Ann(End_{k}(V))$={...
4 votes
3 answers
344 views

Coinvariants of tensor products of Hopf algebras

Let $G$ be a Hopf algebra, considered as a right $G$-comodule in the obvious way. The axioms of Hopf algebras imply that $$ G^{\operatorname{coinv}(G)} == \{g \in G : \Delta(g) = g \otimes 1\} = \...
Todd Claymore's user avatar
4 votes
1 answer
215 views

Explicit examples of finite dimensional, involutive Hopf algebras with traceless antipode?

$\require{AMScd}$ In the paper [1], it is shown that there exist finite dimensional, semisimple Hopf algebras $H$ where the antipode $S:H \to H$ is traceless. Unfortunately, the method of proof in [...
Julian Chaidez's user avatar
3 votes
1 answer
104 views

Irreducibility of product bicomodules

Let $H$ be a Hopf algebra, and $V$ and $W$ a left, and a right, $H$-comodule respectively. The tensor product $$ V \otimes W $$ has an obvious $H$-$H$-bicomodule structure. If $V$ and $W$ are ...
Jake Wetlock's user avatar
  • 1,144
3 votes
0 answers
515 views

What happens geometrically when you take associated-graded (or complete, ...) of a group ring at its augmentation ideal?

I am interested in the following functor from Monoids (in $\text{Set}$) to Graded Lie Algebras (over a fixed field of characteristic $0$). (By "graded" I mean only that my Lie algebras have some ...
Theo Johnson-Freyd's user avatar
2 votes
1 answer
98 views

A weaker version of strongly graded algebras

Let $A = \oplus_{i \in \mathbb{Z}} A_i$ be a graded algebra. We say that it is strongly graded if $A_i.A_j = A_{i+j}$, for all $i,j \in \mathbb{Z}$. Can there be existing a graded algebra such that $$...
Fofi Konstantopoulou's user avatar
2 votes
0 answers
69 views

Is anything known about the center of the Fomin-Kirillov algebra?

Let $\mathcal{B}_{\mathbb{S}_m}$ be the quotient of the Fomin-Kirillov algebra so that its pairing becomes certainly nondegenerate. This algebra is conjecturally isomorphic to the Fomin-Kirillov ...
Christoph Mark's user avatar
2 votes
0 answers
49 views

Permutations of Hopf algebras

Let $A$ be a connected finite dimensional Hopf algebra. Then this algebra is selfinjective and thus there is a permutation $\pi$ with $soc(P_i)=top(P_{\pi(i)})$ for the indecomposable projective $A$-...
Mare's user avatar
  • 26.5k
1 vote
0 answers
97 views

Degree of a commutator in a hyperalgebra or enveloping algebra

Consider a semisimple algebraic group $G$ over an algebraically closed field of arbitrary characteristic and let $\bar U(G)$ denote its hyperalgebra (ie, the restricted Hopf dual of the coordinate ...
Chuck Hague's user avatar
  • 3,637