Skip to main content

All Questions

Filter by
Sorted by
Tagged with
1 vote
0 answers
207 views

Jaw-breaking sum (related to quasi-analytic decompositions of unity — and Hörmander’s Lemma 1.3.6 from LinPDE vol.1)

$$F\left(\frac 1{\text e}\right) ≈ 1-\frac 1{\text e};\qquad\text{here }F(z)≔\sum_{k=1}^\infty \frac{(k-1)^{k-1}}{k!}z^k.$$ The match is at least with 800 decimal places (checked with ...