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3 votes
0 answers
171 views

Nice blowups are universal algebraic fiber spaces?

We say that a proper (maybe projective) morphism $f:X \to Y$ is a universal algebraic fiber space if $f_* O_X = O_Y$ holds universally. (This means: for any morphism $Y' \to Y$, if $X' = Y' \times_Y X$...
iteo's user avatar
  • 39
2 votes
1 answer
186 views

Finite étale cover of factorial ring

Let $A$ be a regular factorial ring. Consider $B=A[X]/(P)$ such that $B$ is finite étale over $A$. When do we have that $B$ is also factorial?
prochet's user avatar
  • 3,472
9 votes
1 answer
1k views

Picard group and reduced schemes

$\DeclareMathOperator\Pic{Pic}$If $A$ is a ring, then we know that $\Pic(A)=\Pic(A_\text{red})$, but for a scheme $X$ it is false in general. On the other hand, we have that $\Pic(X)=H^{1}_{et}(X,\...
prochet's user avatar
  • 3,472
3 votes
0 answers
547 views

Finite Picard group

Does there exist a connected scheme, smooth, proper, and positive-dimensional over $\mathbb{C}$ with finite Picard group? Note that Picard group has cardinality$>1$. Also note that this can not ...
user avatar
8 votes
2 answers
814 views

Are there varieties with non finitely generated Picard group and vanishing irregularity?

Let $X$ be a smooth projective variety over an algebraically closed field $k$. Can it happen that $q(X) := \dim H^1(X,\mathcal O_X) =0$ and $\textrm{Pic} \,X$ is not finitely generated? Certainly, ...
Pitcher's user avatar
  • 83
21 votes
1 answer
1k views

Does every relative curve have a Picard scheme?

More precisely: Let $X \to S$ be a smooth proper morphism of schemes such that the geometric fibers are integral curves of genus $g$. Must the fppf relative Picard functor $\operatorname{\bf ...
Bjorn Poonen's user avatar
  • 23.8k
3 votes
1 answer
600 views

Why is it useful for the (relative) Picard functor to be representable?

I have been studying Chapter 8 of Neron models by Bosch et al. The first part deals with the relative Picard functor. A lot of work is done to make it representable. My question would be why this work ...
user8329099's user avatar