All Questions
7 questions
5
votes
1
answer
271
views
Approximation of Hamiltonian cycles
Let's define the $\texttt{MinHalfSimpCycle}$ search problem: Given $G=(V, E)$ a complete, undirected graph with weights on the edges. We want a simple cycle in $G$ (each vertex appears in it at most ...
- 53
7
votes
7
answers
3k
views
Efficient Hamiltonian cycle algorithms for graph classes
Generally speaking, finding a Hamiltonian cycle is NP-Hard and so tough. But if $G=L(H)$ is the line graph of $H$, then we can reduce the problem of finding a Hamiltonian cycle in $G$ to finding an ...
- 6,962
1
vote
1
answer
178
views
Is Hamiltonian cycle fixed parameter tractable with parameter clique cover?
Let $G$ be connected simple graph.
Clique cover of graph $G$ is partition of the vertices of $G$
into $k$ disjoint cliques $D'_i$.
Given $G$ and $k$-clique cover, can we solve Hamiltonian cycle
in ...
- 25.4k
10
votes
1
answer
513
views
What is the complexity of finding a third Hamilton Cycle in cubic graph?
According to Smith Theorem: if a cubic graph has a hamilton circuit then it must have a second one. SMITH : Given a Hamilton circuit in a 3-regular graph, find a second Hamilton circuit. It is known ...
user39815
6
votes
1
answer
335
views
What is the complexity of counting Hamiltonian cycles of a graph?
Since deciding whether a graph contains a Hamiltonian cycle is $NP$-complete, the counting problem which counts the number of such cycles of a graph is $NP$-hard.
Is it also $PP$-hard in the sense ...
- 121
1
vote
2
answers
603
views
Graph classes where Hamiltonian Cycle and Hamiltonian Path problems have different complexity
While searching The information System on Graph Classes and their Inclusions, I stumbled on several graph classes for which the Hamiltonian Cycle problem is $NP$-complete while the complexity of ...
- 2,993
4
votes
1
answer
724
views
Minimum distance between Hamiltonian cycles in cubic Hamiltonian graph
It is $NP$-hard to find constant factor approximation of longest cycle in cubic Hamiltonian graphs. Therefore, finding a Hamiltonian cycle in a cubic Hamiltonian graph is NP-hard.
By Smith's theorem, ...
- 2,993