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9 votes
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Is simply typed lambda calculus with fixed-point combinator Turing-complete?

There are many sources cite that simply typed lambda calculus extended with fixed-point combinator is Turing complete. For example, Does there exist a Turing complete typed lambda calculus? or the ...
kittyphon's user avatar
  • 101
2 votes
2 answers
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Background for Kierstead terms

I was looking at some slides of John Longley's here, where he mentions "the Kierstead functional" $$\lambda f.f(\lambda x.f(\lambda y.x)) \ ,$$ (where $f$ should be of type $2$, and $x,y$ of ground ...
Basil's user avatar
  • 269