2
$\begingroup$

Jones Lemma is One scale about recognizing that a topological space is not normal. This lemma tells us, if The topological space $X$ has a dense subset $D$ and a closed discrete subset $S$, with the property that $2^{|D|} \le|S|$, it couldn't be a normal space. But I think there is no apparent counterexample about the weaker condition of this lemma as follows.

Q. Is there an example of normal space $X$ which has a dense subset $D$ and a discrete subset $S$ with the property that $2^{|D|} \le|S|$?

$\endgroup$

1 Answer 1

4
$\begingroup$

Yes, take, for example the Sorgenfrey plane $P$. A standard example of a non-normal space. It is separable and its anti-diagonal $\lbrace (x,-x):x\in\mathbb{R}\rbrace$ is closed and discrete, so Jones' Lemma is applicable in this case. Take any Hausdorff compactification of $P$; the result is a separable normal space and now the anti-diagonal is a relatively discrete subspace of the right cardinality.

$\endgroup$
1
  • $\begingroup$ Hello Dear KP Hart. Thank you very much for your tangible example. Your are very good in finding easy conterexamples. (best wishes) $\endgroup$
    – Ali Reza
    Commented May 4, 2012 at 17:27

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .