22
$\begingroup$

My question is motivated by the following recent paper:

http://arxiv.org/abs/1110.6333

Assume you have a metric space $(X,d)$ equipped with a Borel probability measure $\mu$. We can further assume that $X$ is a manifold, if necessary. Let $\{x_{k}\}$ be a sequence of point randomly chosen according to the measure $\mu$. Let us consider $M_{n}$ to be the corresponding distance matrix. More precisely, $$ M_{n}(i,j):=d(x_{i},x_{j}) $$ for $1\leq i,j\leq n$.

Let $\mu_n$ be the distribution of eigenvalues of the (empirical) random matrix $M_{n}$. This is a probability measure on the real line.

I have the following questions:

  1. To what extent can we distinguish two manifolds by looking at the measures $\mu_{n}$? Is it possible for two non-isomorphic manifolds to have the same measures $\mu_{n}$ for all values of $n$.

  2. Can we compute the limit eigenvalue distribution of $M_{n}$ as $n\to\infty$ with the appropriate normalization? For instance, let $X_{n}:=M_{n}/n$ can we compute $$ m_{p}:=\lim_{n\to\infty}{\frac{1}{n}\mathbb{E}\Big[\mathrm{Tr}\big(X_{n}^{p}\big)\Big]} $$ for the the $n$ dimensional torus $S^{1}\times\ldots\times S^{1}$ or the sphere with the uniform measure?

$\endgroup$
3
  • $\begingroup$ Sorry but what do you mean by "non-isomorphic" manifolds? You only consider the linear manifolds or product manifold $S^{1}\times\ldots\times S^{1}$? Or I understand it wrongly? $\endgroup$
    – Henry.L
    Mar 19, 2017 at 19:56
  • $\begingroup$ Nitpick: in question 2 I don't think you mean $n$ to be the dimension of the torus. $\endgroup$ Mar 19, 2017 at 21:03
  • $\begingroup$ @SamHopkins The $n$ is obviously the sample size and the dimension of the torus is fixed, OP just overuse $n$. $\endgroup$
    – Henry.L
    Mar 20, 2017 at 0:56

0

You must log in to answer this question.