Let $M$ be a rank-$2$ vector bundle on a $K3$ surface $S$ such that $h^0(M)\geq 2$ and $h^2(M)=0$. Is it possible that $h^2(\det M)>0$? If yes, can you give me some examples?
1 Answer
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Choose a section $s \in H^0(M)$, let $Z$ be the zero locus of $s$, then we have a right exact sequence $$ M \to \det M \to (\det M)_{|Z} \to 0. $$ Note that $\dim Z \le 1$, hence $H^2((\det M)_{|Z}) = 0$. On the other hand, the functor $H^2$ is right exact (since $S$ is a surface), hence $H^2(M)$ surjects onto $H^2(\det M)$, so $h^2(M) = 0$ implies $h^2(\det M) = 0$.