To fix notation, if $G$ is a compact Lie group, $Rep(G)$ denotes the set of continuous irreducible unitary representations of G, and $\widehat{G}$ denotes the quotient $Rep(G)/\sim$, which identifies isomorphic representations. It is known that every element in $Rep(G)$ has a finite dimension. It is also known that for abelian compact Lie groups, every element of $Rep(G)$ must have dimension 1, which is the case for example for the torus $G=\mathbb{T}^n$. In particular, there is an upper bound for the dimension of elements of $Rep(G)$ in this case. On the other hand, in the case $G=SU(2)$, for each $\ell \in \frac{1}{2}\mathbb{N}_0$ there is exactly one element $t^\ell \in \widehat{SU(2)}$ which have dimension $2\ell+1$, so there is no upper bound for the dimensions of elements in $Rep(SU(2))$.
First question: if $G$ is a compact Lie group and $n \in \mathbb{N}$, when is possible to guarantee that there is $\phi \in Rep(G)$ with $\dim \phi=n$?
Second question: which kinds of compact Lie groups $G$ (besides abelian ones) have this kind of upper bound: there exists $N \in \mathbb{N}$ such that $\dim \phi \leq N$ for all $\phi \in Rep(G)$?
I know that for the second question there is a positive answer in the context of finite groups, and since compact Lie groups have some analogy with finite groups, I wonder if there is at least a partial answer for the second question.