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Let $(M,g)$ be a Riemannian manifold with non-negative Ricci curvature. The Bishop-Gromov volume comparison says that: if $$\alpha_M=\lim_{r\rightarrow\infty}\frac{VolB^M(p,r)}{\omega_nr^n},$$ then $0\leq \alpha_M\leq 1$. Now suppose $\Gamma$ be a non-trivial subgroup of $\pi_1(M)$. Consider the covering space $\rho:\bar{M}/\Gamma\rightarrow M$, where $\bar{M}$ is the universal cover of $M$. Take $$\alpha_{\bar{M}/\Gamma}=\lim_{r\rightarrow\infty}\frac{VolB^{\bar{M}/\Gamma}(q,r)}{\omega_nr^n},$$ where $\rho(q)=p$ and $VolB^{\bar{M}/\Gamma}(q,r)$ is the ball in $\bar{M}/\Gamma$. $\bar{M}/\Gamma$ has the pull back metric $\rho^*g$.

Is there any relation between $\alpha_M$ and $\alpha_{\bar{M}/\Gamma}$? It is clear that $0\leq \alpha_{\bar{M}/\Gamma}\leq 1$, but I am not able to find a relation between $\alpha_M$ and $\alpha_{\bar{M}/\Gamma}$.

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    $\begingroup$ Theres an inequality between then since balls in the cover will have larger volume. $\endgroup$
    – Ian Agol
    Commented Jun 12 at 17:49
  • $\begingroup$ Thank you very much sir for your comment. $\endgroup$ Commented Jun 12 at 17:59

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