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Let $G$ be a connected complex reductive group. Suppose $G$ acts on a smooth complex affine variety $X$. Assume the stabiliser $G_x$ of every point $x\in X$ is finite. Is it true that $X/\!/G$ is an orbifold? I.e., does $X/\!/G$ have, at worst, quotient singularities?

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    $\begingroup$ If $X$ is singular then this is certainly not true $\endgroup$
    – Henri
    Commented Apr 10 at 9:20
  • $\begingroup$ Sorry I meant to include the word smooth. It is corrected now. $\endgroup$
    – Dr. Evil
    Commented Apr 11 at 7:10
  • $\begingroup$ How about Luna's slice theorem? This post. $\endgroup$
    – Yikun Qiao
    Commented Apr 12 at 7:19
  • $\begingroup$ The Luna slice theorem does indeed seem to be relevant. Although I found the answer to this post better suited for the question. If somebody can expand this into an answer, I would be grateful. mathoverflow.net/questions/435428/… $\endgroup$
    – Dr. Evil
    Commented Apr 13 at 19:41

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