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Are there any good reference to tackle the problem below? Or, are there any know result?

Problem
Let $f_1...f_n\in \mathbb{Z}[x_1,..,x_n]$ and $V:\mathbb{R}^n\rightarrow \mathbb{R}^n$ be a vector field on $\mathbb{R}^n$ defined by each $f_i$.

Let's consider a initial value problem for $x(t)\in (\mathbb{Z}[t])^n$.
$$ \begin{cases} \dfrac{dx(t)}{dt}=V(x(t)),\\ x(0)=\mathbf 0\in \mathbb{R}^n \end{cases} $$
Quesstion. If this equation has a polynomial solution in $(\mathbb{Z}/p\mathbb{Z}[t])^n$ for every sufficiently large prime $p$, then does the original equation have polynomial solution in $(\mathbb{Z}[t])^n$?

Here, $F\in (\mathbb{Z}/p\mathbb{Z}[t])^n$ is a solution of this equation, if $F$ is a formal solution of a differential equation with $\tilde{V}: (\mathbb{Z}/p\mathbb{Z})^n\rightarrow (\mathbb{Z}/p\mathbb{Z})^n$ which is a reduction of $V$ mod $p$

Moreover what if $V$ is $p$-closed for each sufficiently large $p$ i.e. $V^p=0$ as derivation on $\mathbb{Z}/p\mathbb{Z}[x_1,...,x_n]$.
Bost's paper about algebraicity of foliaiton seems related to this question but I don't know whether I can I apply techniques used there.

Full reference:
Jean-Benoît Bost, "Algebraic leaves of algebraic foliations over number fields", Publications Mathématiques de l'IHÉS, Tome 93 (2001), pp. 161-221. MR1863738, Zbl 1034.14010.

Since there may be counterexamples, you can freely add additional conditions.

I think this is a kind of non linear version of Grothendieck-Katz conjecture.

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  • $\begingroup$ How could a solution $x(t)$ belong to $\mathbb{Z}/p\mathbb{Z}[x_1,...,x_n]$? $\endgroup$ Commented Mar 27 at 11:06
  • $\begingroup$ Sorry, I made a huge mistake and I correceted the question. $\endgroup$
    – George
    Commented Mar 27 at 11:20
  • $\begingroup$ Is time discrete in this problem? I mean, how does $x(t)$ belong to $(\mathbb{Z}[t])^n$ for small $t$? $\endgroup$
    – kindasorta
    Commented Mar 27 at 21:56
  • $\begingroup$ A solution of this differential equation is defined with formal method i.e a polynomial with integer coefficient is a solution if it's formal derivative satisfy the equation. $\endgroup$
    – George
    Commented Mar 29 at 14:44
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    $\begingroup$ This is false if $V$ is allowed to be a tuple of rational functions instead of polynomials. Is there a reason to think the polynomial case is different? $\endgroup$
    – Will Sawin
    Commented Mar 29 at 17:59

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