This question is about a technical imprecision which is easily avoidable but whose details I'd like to understand better. When we refer to "the consistency strength of $\mathsf{PA}$" (say) we aren't properly referring to $\mathsf{PA}$ as a set; rather, we care about the specific way in which $\mathsf{PA}$ is enumerated. "The set of sentences which $\mathsf{ZFC}$ proves are $\mathsf{PA}$-axioms" is another way to define the same (hopefully!) set, but properly speaking it is equiconsistent with $\mathsf{ZFC}$.
It occurs to me that I don't know whether the usual description of the $\mathsf{PA}$ axioms is optimal with respect to consistency strength. Below, let $(T_e)_{e\in\omega}$ be some appropriate enumeration of the c.e. theories. Suppose WLOG that $T_0$ is the usual c.e. presentation of $\mathsf{PA}$.
Question: Is there an index $e$ such that ("extensionally") $T_e=\mathsf{PA}$ but $\mathsf{PA}+\mathsf{Con}(T_e)\not\vdash \mathsf{Con}(T_0)$?
One natural way to try to get a positive answer to this question is to enumerate the axioms of $\mathsf{PA}$ very slowly, waiting for contradictions, along the following lines: given a $\mathsf{PA}$-provably-total computable function $f$, let $T_f$ be the c.e. theory which enumerates the $n$th axiom of $\mathsf{PA}$ in the usual ($T_0$) sense iff there is no contradiction in $\mathsf{PA}$ using fewer than $f(n)$-many symbols. As long as $f$ is reasonably-fast-growing (say, dominating $n\mapsto 2^n$) it seems "$\mathsf{PA}$-believable" that $T_f$ detects a contradiction before falling prey to it. On the other hand, I don't see how to show the consistency of $\mathsf{PA}+\mathsf{Con}(T_f)+\neg\mathsf{Con}(T_0)$ for any specific $f$.
(This older question seems thematically similar, but I don't actually see a concrete connection.)