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Let $K$ be an algebraically closed field and consider the category $\text{Bun}$ of (finite dimensional) vector bundles over a $K$-variety $X$. Consider also the category of $\mathbb{G}^\times$-principal bundles over $X$, $\text{Bun}_0$. $\mathbb{G}^\times$-principal bundles are equivalent to maps into $\mathbb{P}^{\infty}$, and with this I have a much clearer picture of how $\text{Bun}_0$ works in algebraic geometry e.g. with the clutching construction.

However, the cohomology classes in algebraic geometry are more typically understood as being valued in $\text{Bun}$ (not just $\text{Bun}_0$). Somehow it is possible to extend from the case for line bundles so long as $l_1 \oplus \cdots \oplus l_n$ is sent to $\text{cl} (l_1) \cup \cdots \cup \text{cl}(l_n)$. I see of course that such an extension is unique when it exists, but I do not as of yet understand why we can consistently extend maps from $\text{Bun}_0$ to $\text{Bun}$.

So my question is, what is an extension theorem that goes something like this (ideally with a reference):

A natural transformation from $\eta : \text{Bun}_0 = \text{Bun}_0(X) \implies F$ between contra variant functors on $K$-varieties always extends to a natural transformation $M(\eta) : \text{Bun} \implies F$ preserving the apparent product structure given by $* \rightarrow X \leftarrow X \times X$.

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    $\begingroup$ This is called the splitting principle. A reference is [Weibel, The K-book, Chapter 2, p33, Chern splitting priciple]. $\endgroup$
    – Z. M
    Commented Jan 23, 2023 at 20:31
  • $\begingroup$ @Z.M, I think that that is an answer! $\endgroup$
    – LSpice
    Commented Jan 23, 2023 at 21:14
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    $\begingroup$ @Z.M yes- post it in a box to get credit. $\endgroup$
    – user30211
    Commented Jan 23, 2023 at 22:04

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