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I occasionally come across a new piece of notation so good that it makes life easier by giving a better way to look at something. Some examples:

  • Iverson introduced the notation [X] to mean 1 if X is true and 0 otherwise; so for example Σ1≤n<x [n prime] is the number of primes less than x, and the unmemorable and confusing Kronecker delta function δn becomes [n=0]. (A similar convention is used in the C programming language.)

  • The function taking x to x sin(x) can be denoted by x ↦ x sin(x). This has the same meaning as the lambda calculus notation λx.x sin(x) but seems easier to understand and use, and is less confusing than the usual convention of just writing x sin(x), which is ambiguous: it could also stand for a number.

  • I find calculations with Homs and ⊗ easier to follow if I write Hom(A,B) as A→B. Similarly writing BA for the set of functions from A to B is really confusing, and I find it much easier to write this set as A→B.

  • Conway's notation for orbifolds almost trivializes the classification of wallpaper groups.

Has anyone come across any more similar examples of good notation that should be better known? (Excluding standard well known examples such as commutative diagrams, Hindu-Arabic numerals, etc.)

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    $\begingroup$ In set theory we write ${}^B A$ for the set of functions from $B$ to $A$. $\endgroup$ Commented Oct 20, 2010 at 20:54
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    $\begingroup$ I've always assumed that the notation $A^B$ is because of the "exponential law" $(A^B)^C = A^{B\times C}$ ... $\endgroup$ Commented Oct 20, 2010 at 23:18
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    $\begingroup$ Yes, among other things. Also $A^B\times A^C=A^{B+C}$, where $+$ is disjoint union. But all the great reasons for it don't help for our mind thinking that maps start with the source and end with the image, not the other way round. $\endgroup$ Commented Oct 20, 2010 at 23:20
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    $\begingroup$ Arabic numerals ? Ah yes, they were transmitted to Europe by the Arabs. $\endgroup$ Commented Oct 21, 2010 at 3:29
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    $\begingroup$ Isn't $x \mapsto f(x)$ commonplace? As for homomorphisms, they are not simply maps, and $\mathrm{Hom}(A, B)$ denotes the whole class, while $A \to B$ denotes a single mapping. $\endgroup$ Commented Oct 21, 2010 at 3:38

81 Answers 81

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Since this one is on the front page again: In my personal notes, I have started writing sums/integrals over complicated index sets as $\sum \left( \text{summand} \mid \text{condition} \right)$, rather than a subscript. EG $$\sum {\large (} \log p \mid p \ \text{prime}, p \equiv 1 \bmod 4,\ p \leq N {\large )}$$ instead of $$\sum_{\substack{p \ \text{prime} \\ p \equiv 1 \bmod 4 \\ p \leq N}} \log p.$$

I find it a lot more readable. Additional benefits (1) it is reminiscent of set builder notation like $\{ \log p \mid p \ \text{prime}, p \equiv 1 \bmod 4,\ p \leq N \}$ (2) it means that the pairing between differential forms and cycles actually looks like a bilinear pairing.

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  • $\begingroup$ This is very reminiscent of unordered sums: If $\mathcal{F}(X)$ is the set of finite subsets of $X$, then set inclusion is directed. Any function $f \colon X \to \mathbb{R}$ thus induces a net $\mathcal{F}(X) \to \mathbb{R}$ given by $A \mapsto \sum_{x \in A} f(x)$. The unordered sum $\sum_{x \in X} f(x)$ is the limit of this net if it exists. Given a set $B \subseteq \mathbb{R}$ one could then let $f \colon B \to \mathbb{R}$ be $f(b)=b$ and write $\sum B$ for the unordered sum $\sum_{b \in B} f(b)$. One can then even use set builder notation. I might start doing that! $\endgroup$
    – Danny
    Commented Jun 11 at 3:45
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Using $(a, b, ... )$ is handy to denote a column vector, which is the transpose of the row vector $[a, b, ... ]$, especially in linear text. Correspondingly, all displayed matrices should be written with brackets, not parentheses. This notation agrees with the usual identification of coordinates with column vectors.

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    $\begingroup$ I take it you also hate having to write the transpose when you're constrained to writing on one line? :) $\endgroup$ Commented Oct 21, 2010 at 11:45
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    $\begingroup$ Yes, particularly when stacking vectors $a, b, ... $, in which case you have to write the artificial $[a^T, b^T, ... ]^T$ without this convention. $\endgroup$ Commented Oct 21, 2010 at 13:52
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    $\begingroup$ It is, of course, not $[a, b, \dots]^T$ but $[a\;b\;\dots]^T$. This is an awful convention because even once you remind yourself why the $T$ is there you (or I at least) am not convinced that it has any meaning other than to satisfy a badly chosen precedent. I don't know why anyone would vote this down. $\endgroup$
    – Ryan Reich
    Commented Oct 21, 2010 at 16:27
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    $\begingroup$ Don't forget the invariant literature which uses $\left[v_1,...,v_n\right]$ not for the matrix formed by the columns $v_1$, ..., $v_n$, but for its determiannt... $\endgroup$ Commented Oct 21, 2010 at 17:04
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    $\begingroup$ I personally prefer the notation $(a_1,\ldots,a_n)$, with commas, or equivalently $(a_1\;a_2\;\ldots\;a_n)^{\mathrm{T}}$ or $[a_1\;a_2\;\ldots\;a_n]^{\mathrm{T}}$ for column vectors. And $(a_1\;a_2\;\ldots\;a_n)$ or $[a_1\;a_2\;\ldots\;a_n]$ for row vectors. $\endgroup$
    – Qfwfq
    Commented Jan 19, 2021 at 0:00
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The lack of a nice obviously symmetric notation for $\binom{a+b}{b}$ has bothered me; Dijkstra suggested in EWD 782 the notation $P(a,b)$, generalizing it also to $P(a_1,\ldots,a_k)$ for $\binom{a_1+\ldots+a_k}{a_1,\ldots,a_k}$. (Though I certainly disagree with him about $\binom{n}{k}$ being useless - you certainly do want to think about it that way a lot of the time.) I haven't actually had any reason to use this since I saw it but I can certainly think of times I would have.

Also the double-parentheses multichoose notation $\left(\!\binom{n}{k}\!\right)$ is nice because it lets you say "...and this is n multichoose k (which is equal to this binomial coefficient)" instead of just jumping directly to a binomial coefficient whose relevance may not be immediately obvious. But I suppose that's not really on the level of giving you a better way to look at things.

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    $\begingroup$ Isn't there a nice obviously symmetric notation for ${a+b} \choose b$, namely ${a+b} \choose {a,b}$? $\endgroup$
    – Rasmus
    Commented Oct 21, 2010 at 18:34
  • $\begingroup$ Oh, true. That is a good point. It looks a bit clunky but it works. $\endgroup$ Commented Oct 21, 2010 at 20:28
  • $\begingroup$ $\left(\!\binom{n}{k}\!\right)$ $\endgroup$
    – JBL
    Commented Oct 22, 2010 at 13:26
  • $\begingroup$ is given by \left(\!\binom{n}{k}\!\right) $\endgroup$
    – JBL
    Commented Oct 22, 2010 at 13:27
  • $\begingroup$ $\binom{a+b}{a,b}$ often means something else when $a=b$, namely the number of ways of partitioning $2a$ into two groups of size $a$. Thus $\binom{4}{2,2}$ is $3$ not $6$. $\endgroup$
    – David MJC
    Commented Nov 10, 2010 at 19:40
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In the notation of Time scale calculus, the ordinary calculus derivative df/dt and the forward difference operator $\Delta f $ are both written as $f^\Delta$. Indefinite sums and indefinite integrals are both written as $\int{f(t)\Delta t}$ and called indefinite integrals. The context would say $\mathbb{T}=\mathbb{Z}, \mathbb{T}=\mathbb{R}$ or other $\mathbb{T}\subset\mathbb{R}$.

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  • $\begingroup$ What do you mean by "indefinite integral"? I used to hear this term referred to the "family of primitives" of a given function, like in: $\int f(x) dx=F(x)+C$ $\endgroup$
    – Qfwfq
    Commented Oct 22, 2010 at 13:27
  • $\begingroup$ (btw, it wasn't me to downvote) $\endgroup$
    – Qfwfq
    Commented Oct 23, 2010 at 18:17
  • $\begingroup$ Yes, when the time-scale is the real numbers, the indefinite integral $\int f(t)\Delta t=\int{f(x)dx}=F(x)+C$ and when time=integers, $\int f(t)\Delta t=\Delta^{-1}f(x)=F(x)+C$ (not the same F in each case though of course). $\endgroup$ Commented Oct 27, 2010 at 12:04
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Multi-factorials are handy. Sometimes results can be expressed compactly by introducing a double factorial or possibly higher factorial. For example

$$\int_0^{\pi/2} \sin^{2n+1} \theta \:\: d\theta = \frac{(2n)!! }{ (2n+1)!!}$$

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    $\begingroup$ I wish there were a notation that didn't scream "iterated factorial", though (not that one sees this very much). I forget: does $n?$ mean anything? The question mark is handy because it suggests having to make a choice, as in "even or odd?" $\endgroup$
    – Ryan Reich
    Commented Nov 16, 2010 at 10:48
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    $\begingroup$ The question mark has a meaning in C and programming languages derived from C. The notation a ? b : c; means to do b if a is true, otherwise do c. The question mark also means "optional" in regular expressions. For example, the regular expression ab?c matches abc or ac. I don't know whether either of these notations would make sense imported into math. On a related note, sometimes I would like to import C's % operator into math notation. $\endgroup$ Commented Nov 16, 2010 at 23:30
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    $\begingroup$ True, but C also doesn't have a factorial operator, and ! means something entirely different again. There's not much reason to make mathematical notation agree with programming design choices. As for %, we always have "mod". $\endgroup$
    – Ryan Reich
    Commented Nov 29, 2010 at 9:08
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    $\begingroup$ The problem with "mod" is that it is usually an equivalence relation and not a function. That is, you see "a equiv b mod m" more than "a mod m". I'm not sure the latter is common notation or that people agree in detail what it means. $\endgroup$ Commented Nov 29, 2010 at 15:22
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I think that Inuit numerals are cool. (http://en.wikipedia.org/wiki/Inuit_numerals) They are useful for vigesimal type things.

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    $\begingroup$ Now I wonder where in mathematics you would like to do actual vigesimal calculations? $\endgroup$ Commented Dec 19, 2011 at 10:44
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When I teach topology, I write $A\stackrel{\textrm{o}}{\subset} X$ to mean that A is an open subset of the topological space $X$, and I write $A \sqsubset X$ to mean that $A$ is a closed subset of $X$. I think it would drive me crazy to write the words open and closed constantly.

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  • $\begingroup$ I believe this notation (or something similar) is due to Chan-Ho Suh, who used it in his homework in a course Marshall Cohen taught at Cornell, and then Marshall started using it in his classes. $\endgroup$
    – Dan Ramras
    Commented Dec 19, 2021 at 5:08
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    $\begingroup$ One could do something more symmetrical for closed sets, like $A\stackrel{\textrm{c}}{\subset} X$, but I suspect it would be easy to mistake c for o or vice versa, maybe especially in handwriting. $\endgroup$
    – Dan Ramras
    Commented Dec 19, 2021 at 5:08
  • $\begingroup$ Personally I put a small circle / small diagonal dash on the lower bar of the $\subset$ to denote an open / closed subset. One can do the same for inclusion maps $\hookrightarrow$, this is a relatively common notation in algebraic geometry for open / closed immersions. $\endgroup$ Commented Dec 19, 2021 at 9:59
  • $\begingroup$ Perhaps one could also consider the classics $G$ and $F$ for open and closed, though of course $F$ might clash with "finite". $\endgroup$
    – Danny
    Commented Jun 11 at 3:49
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Cauchy-Binet as a generalized Pythagoras theorem.

Let $X$ be an $ n \times k$ matrix with $n \ge k$. For any $k$-index $I=i_1...i_k, \; 1 \le i_1 < ... < i_k \le n$, there is some advantage to denote by $X_I$, the determinant of the $k \times k$ submatrix of $X$ with rows indexed by $I$. For any two such $X,Y$, we can state the Cauchy-Binet formula as a pairing $$ \det (X^TY)= \sum_{I} X_I Y_I $$ where the sum is over all $n \choose k$ $k$-indices. This is a Pythagoras theorem for $X=Y$ since it says that the the volume-squared of the parallelepiped spanned by the $k$ columns of $X$ in $\mathbb{R}^n$ is the sum of squares of the volume of the projections on the $n \choose k$ $k$-dimensional coordinates.

For any $n \times m$ matrix $A$ with $m,n \ge k$ and $k$ indices $I,J$, we also denote by $A_{IJ}$ the determinant of the $k \times k$ submatrix of $A$ with rows indexed by $I$ and column indexed by $J$. Then for $X(m \times k)$ and $Y(n \times k)$, we have by Cauchy-Binet twice, $$ \det(X^TAY)=\det(X^T(AY))=\sum_{I}X_I(AY)_I =\sum_I X_I \det(A^IY)=\sum_I X_I \sum_J A_{IJ} Y_J,$$ where $A^I$ is the $k \times n$ matrix given by the rows of $A$ indexed by $I$ and we note that $(AY)_I= \det(A^IY)$ and $(A^I)^T_J=A_{IJ}$. This notation thus allows us to view Cauchy-Binet (usually stated with $m=n,A=I$) as an extension of the usual $x^TAy=\sum_{ij}A_{ij}x_iy_j$ for $k=1$.

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    $\begingroup$ This is not really about notation, but it's a very good point. $\endgroup$ Commented Nov 2, 2010 at 0:09
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I use the notation

$V \oplus^{\perp}W$

to denote orthogonal direct sum [Edit: direct sum of, say, subspaces of a given inner-product space].

Or

$(M,g) \times^{\perp} (N,g')$, or simply $M \times^{\perp} N$, to denote (orthogonal) cartesian product of Riemannian manifolds.

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  • $\begingroup$ I'd like to know why this was downvoted: you simply don't like the symbol, or there's some deeper reason? $\endgroup$
    – Qfwfq
    Commented Oct 23, 2010 at 22:13
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    $\begingroup$ I didn't downvote it, but I don't like the notation because it is redundant and emphasizes the wrong thing. For vector spaces, there is no intrinsic inner product with respect to which a direct sum can be either orthogonal or not. If you have two inner product spaces, then the direct sum is always orthogonal unless specified otherwise, because there is no one way to do it otherwise. Likewise for the direct product of two manifolds with a Riemannian metric. It is better to have a notation for when the sum or product is not orthogonal, and to specify how. $\endgroup$
    – Ryan Reich
    Commented Nov 16, 2010 at 11:00
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    $\begingroup$ I have seen that some authors use the notation $V\obot W$ for this purpose (provided by mathabx package in latex), see tex.stackexchange.com/a/61882/39306. $\endgroup$
    – Name
    Commented May 27, 2015 at 17:50
  • $\begingroup$ As an alternative, Steven Roman uses $V \otimes W$ for orthogonal direct sums. Though I think Ryan has a good point. $\endgroup$
    – Danny
    Commented Jun 11 at 3:52
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Instead of writing $$|x-y|\le \varepsilon,$$ I used to write $$x\lessgtr y\pm \varepsilon.$$ You may read it as $x$ is more-or-less $y$ plus-minus $\varepsilon$.

One may also write something like $$x\lessgtr e^{\pm\varepsilon}\cdot y$$ which is much better than $$|\ln(y/x)|\le\varepsilon$$

It is easier to read, especially if instead of $x$ and $y$ you have long expressions.

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    $\begingroup$ What would you write for $|x-y|\geq \epsilon$? $\endgroup$ Commented Jan 24, 2013 at 23:24
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    $\begingroup$ I'm not happy about the "principle" in Anton's reply to Nate's comment. In the body of the question, the upper inequality (with $<$ and $+\varepsilon$) and the lower inequality (with $>$ and $-\varepsilon$) are to be understood as combined by "and", whereas in the comment, the upper and lower inequalities are intended to be combined by "or". Allowing both uses of the notation seems to be inviting confusion. $\endgroup$ Commented Jan 26, 2013 at 16:22
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    $\begingroup$ Andreas, you are right, I made this reply without much thinking :) $\endgroup$ Commented Jan 30, 2013 at 19:10
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    $\begingroup$ Actually, I like $x =^\epsilon y$ for this concept. $\endgroup$
    – Lee Mosher
    Commented Feb 2, 2013 at 23:43
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    $\begingroup$ @LeeMosher, as a $p$-adic analyst I like this, but surely those poor folks for whom $=^\epsilon$ is not transitive will not be so happy. :-) $\endgroup$
    – LSpice
    Commented May 18, 2015 at 19:44
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UMBRAL NOTATION (courtesy of Blissard)

$$(q.)^n = q_n$$

Concise, elegant, and suggestive, it often allows for both brevity and comprehensibility of presentation and short derivations of operational results.

Examples of umbral variables:

$q.^n = q_n = d$, a constant quantity, maybe a single variable or polynomial,

$q.^n = q_n = d^n $, a constant quantity raised to powers,

$q.^n = q_n = x^n$, a variable raised to a power,

$q.^n = b.^n = b_n$; an element of a sequence of numbers, such as the Bernoulli,

$q.^n = B.(x)^n = B_n(x)$, an element of a sequence of polynomials, .e.g., Bernoulli,

$q.^n = (.)!^n = (n)!$, an expression containing an integer parameter,

$q.^n = \binom{x}{.}^n = \binom{x}{n} $, ditto,

$q.^n = M.^n = M_n$, a sequence of matrices, differential ops, ... whatever.

The umbral maneuver in more complex expressions:

  1. reduce an expression that contains the umbral entity to an analytic series in monomial powers of $q.$ when possible

  2. then lower the positive integer exponent to a subscript

  3. when in doubt apply

$$e^{q.xD_y} \; f(y) \; |_{y=0} = f(q.x +y) \;|_{y=0} = f(q.x) \;$$

  1. sensible results can often be obtained for functions not analytic at the origin from

$$f(q.x) := e^{-(1-q.)x D_y} \; f(y) \; |_{y=x} = f(x-(1-q.)x) = f((1-(1-q.))x) $$

(See below on Newton interpolation. E.g., with $f(x)=x^s$, then $f(q.x) = (q.x)^s = q_s\; x^s \; := (1-(1-q.))^sx^s \; $ when convergent.)

Basic umbral operations:

  1. binomial convolution for commuting quantities:

$$c_n = c.^n = (a. + b.)^n = \sum_{k=0}^n \binom{n}{k} \; a.^k \; b.^{n-k} = \sum_{k=0}^n \binom{n}{k} \; a_k\; b_{n-k},$$

  1. formation of e.g.f.s and o.g.f.s:

$$E(t) = e^{q.t} = \sum_{n \geq 0} \; q.^n \; \frac{t^n}{n!} = \sum_{n \geq 0} \; q_n \; \frac{t^n}{n!}$$

and, with $q_0 =1$,

$$O(t) = \frac{1}{1-q.t} = \sum_{n \geq 0} (q.t)^n = \sum_{n \geq 0} q_n \; t^n = e^{\bar{q}.t}= \bar{O}(t)$$

with $\bar{q}_n = n! \; q_n$.

Then multiplication of formal series is

$$EA(t) \; EB(t) = e^{a.t} \; e^{b.t} = e^{(a.+b.)t} = e^{c.t} = EC(t) \; .$$

We can even disregard convergence of both series if we are interested only in formal compositional or multiplicative inverses or the formal Laplace transform of an e.g.f. to an o.g.f. since the production of the $n$-th coefficient of the target series depends only on the coefficients of order $n$ or less of the source series for these transformations.

Brevity and intelligibility in umbral versus conventional presentations:

The Euler transformation for e.g.f.s in umbral notation

  1. $$ e^{a.x} = e^x \; e^{-(1-a. )x}$$

versus conventional notation

  1. $$ \sum_{n \geq 0} a_n \; \frac{x^n}{n!} = e^x \; \sum_{n \geq 0} (-1)^n \; [\; \sum_{k=0}^n \; (-1)^k \; \binom{n}{k} \; a_k \; ] \; \frac{x^n}{n!} \; ,$$

and derivation of the conventional formula via the umbral,

  1. $$ e^{a.x} = e^x \; e^{-x} e^{a.x} = e^x \; e^{-(1-a. )x}$$

$$ = e^x \; \sum_{n \geq 0} (-1)^n \; (1-a.)^n \; \frac{x^n}{n!} = e^x \; \sum_{n \geq 0} \; (-1)^n \; [\; \sum_{k=0}^n \; (-1)^k \; \binom{n}{k} a_k \; ] \; \frac{x^n}{n!} \;.$$

(23 keys tapped for eqn. 1 versus 102 keys for 2, not counting the appreciable difference in taps for blank spacing and latex spacing for readability. I could have saved a good fraction of a lifetime of math work by being able to use umbral notation in symbolic apps, study, and publications rather than sigma gymnastics.)

Natural generalizations via umbralization--monic to partition polynomials:

Stirling polynomials of the first kind, related to cyclic permutations, have the e.g.f.

$$e^{St1.(x)t} = e^{x \ln(1+t)} = (1+t)^x\; ,$$

and Stirling polynomials of the second kind, related to partitions of sets,

$$e^{St2.(x)t} = e^{x (e^t-1)} \, .$$

Flexibility and precision is afforded if some notation is used to indicate at what level the umbral exponent lowering is to occur. For example, with $\langle \cdots \rangle$ denoting evaluation of the expression between the angular brackets after reduction to a series in the umbral quantity and with $q_0=1$,

$$\langle \; e^{-\ln(1-q.t)} \;\rangle = \langle \frac{1}{1-q.t}\rangle = \langle \sum_{n \geq 0} q.^n \; t^n \; \rangle = \sum_{n\geq 0} \langle q.^n \rangle \; t^n =\sum_{n \geq 0} q_n \; t^n $$

and

$$e^{-\langle \ln(1-q.t)\rangle} = \exp[\langle \sum_{n \geq 1} q.^n \frac{t^n}{n}\rangle] = \exp(\sum_{n \geq 1} q_n \frac{t^n}{n}) ,$$

which is the e.g.f. for the cycle index partition polynomials of the symmetric groups, a.k.a. the Stirling partition polynomials of the first kind, OEIS A036039.

The natural generalization of the Stirling polynomials of the second kind is via the umbralization, for $q_0 = 1$,

$$e^{\langle e^{q.t}-1 \rangle} = \exp[ \; \sum_{n \ge 1} \; q_n \frac{t^n}{n!} \; ], $$

giving the complete Bell polynomials of the Faa di Bruno composition formula, a.k.a. the Stirling partition polynomials of the second kind, A036040.

Including an extra variable as in

$$e^{x\langle e^{q.t}-1 \rangle} = e^{Bell.(q_1,..,q.;x)t}$$

and

$$e^{-x\langle\ln(1-q.t)\rangle} = e^{Cyc.(q_1,..,q.;x)t}$$

allows better tracking of block sizes and combinatorics within each partition polynomial. (Note $q_n$ could be a commuting sequence of wedge products, curvature forms, or matrices, just as well as integers, giving basic formulas for the Chern and Pontryagin characteristic class polynomials.)

Now for a little umbral mojo,

$$ e^{St1.(St2.(x)) \; t} = e^{St2.(x) \; \ln(1+t)}=e^{x \; (\exp(\ln(1+t))-1)} = e^{xt} \; ,$$

so the two sets of binomial Sheffer polynomial sequences are an inverse pair under umbral composition; i.e.,

$$St1_n(St2.(x)) = x^n = St2_n(St1.(x)) \; .$$

This is reflected in their lower triangular coefficient matrices being a matrix inverse pair. The same umbral compositional inverse and matrix relationships hold for any Sheffer polynomial sequence. For a pair of inverse/reciprocal Appell Sheffer sequences, this is due to their moment e.g.f.s being multiplicative inverses rather than compositional inverse. The generic Sheffer sequence has a mix of these conditions, belonging to the semidirect product of the Appell and binomial Sheffer subgroups.

Actions of diff op often become more transparent with umbral calculus and/or underlying combinatorics are revealed:

With $a.$ treated as independent of $x$ and $D = d/dx$ for $f(x)= e^{b.x}$,

$$e^{a.D_x} \; f(x) = f(a.+x) = e^{b.(a.+x)}.$$

For the Bernoulli number and polynomials (or any Appell Sheffer sequence),

$B_n(x) = e^{b.D} \; x^n = (b.+x)^n$,

$D \; B_n(x) = D \; (b.+x)^n = n \; (b.+x)^{n-1} = n \; B_{n-1}(x)$

$e^{a.D} \; B_n(x) = B(x + a.) = (x+b.+a.)^n = (B.(x)+a.)^n = (B.(a.)+x)^n \; .$

Adopt the additional notational convenience $(:AB:)^n := A^nB^n$. Alternatively, we could use $q.^n = q_n = A^nB^n$, but this would veil aspects/intuitions inherited from the properties of the derivative.

From our previous feat of umbral mojo,

$$St1_n(xD) = n! \; \binom{xD}{n} = ST1_n(ST2.(:xD:) = \; :xD:^n \; = x^nD^n,$$

consistent with the actions

$xD \; [x^n] = n x^n$,

$(1 + a.)^{xD} \; [x^n] = (1 + a.)^{n} \; x^n$,

and

$(1 + a.)^{xD} \; f(x) = \sum_{n \geq 0} a_n \; \binom{xD}{n} \; f(x) = e^{a.:xD:} \; f(x) = f((1+a.)x).$

The operational definition of the Stirling polynomials of the second kind is

$$(xD)^n = (St2.(:xD:))^n = St2_n(:xD:).$$

From this the e.g.f. given above for the polynomials can easily be derived, and, consequently,

$$e^{txD} \; f(x) = e^{t \; St2.(:xD:)} \; f(x) = e^{(e^t-1):xD:} \; f(x)$$

$$ =f((e^t-1)x + x) = f(e^t x),$$

a dilation, consistent with $e^{txD} \; x^n = e^{tn} \; x^n$.

The Lah polynomials $L_n(x)$ (the normalized, unsigned Laguerre polynomials of order -1, related to partitions of sets into ordered sets or lists) have several useful Stokes-Rodrigues diff op reps,

$$ x \; :Dx:^n \; x^{-1} = x \; D^n x^n x^{-1} = x^{-n+1} (xDx)^n x^{-1} = x^{-n} (x^2D)^n = L_n(:xD:) ,$$

and the e.g.f.

$$e^{L.(x)t} = e^{x \frac{t}{1-t}},$$

so

$$ e^{tx^2D} \; f(x) = e^{t \; :xL.(:xD:):} \; f(x) = e^{:\frac{tx^2}{1-tx}D:} \; f(x)$$

$$= f(\frac{tx^2}{1-tx} + x) = f(\frac{x}{1-tx}), $$

a special linear fractional, or Moebius, transformation.

(The inverse ops to the translation, $e^{tD}$; dilation, $e^{txD}$; and special linear fractional, $e^{tx^2D}$, transformations of SL2 are given by negating $t$, which is equivalent to additive ($t+(-t)=0$), multiplicative ($e^t \cdot 1/e^t =1$), and compositional inversion ($\frac{x}{1-tx}|_{x \to\frac{x}{1+tx}}=x$), respectively. SL2 becomes associated to the underlying combinatorics of the binomial Sheffer polynomials $St2_n(x)$ and $L_n(x)$ via the umbral symbolic calculus.)

Interpolation methods and results of integral transforms are naturally suggested and expressed in umbral notation:

Laplace transform of e.g.f. to o.g.f.s with $q_0=1$:

$$\int_{0}^\infty \; e^{q.xt} \; e^{-t} dt = \int_{0}^\infty \; e^{-t(1-q.x)} dt = \frac{1}{1-q.x}$$

Mellin transform interpolation to continuous indices (related to Ramanujan's master formula, e.g., the Bernoulli polynomials are essentially discrete samples of the Hurwitz zeta function):

$$ q_{-s} = (q.)^{-s} := \int_{0}^\infty \; e^{-q.t} \; \frac{t^{s-1}}{(s-1)!} \; dt$$

Newton interpolation to continuous indices:

$$q_s = (q.)^s = (1-(1-q.))^s = \sum_{m=0}^\infty \; (-1)^m \; \binom{s}{m} \;\sum_{k=0}^m \; (-1)^k \; \binom{m}{k} \; q_k$$

$$= \int_{0}^\infty \; e^{-(1-(1-q.))t} \; \frac{t^{-s-1}}{(-s-1)!} \; dt= \int_{0}^\infty \; e^{-t} \; e^{(1-q.)t} \; \frac{t^{-s-1}}{(-s-1)!} \; dt$$

$$= \int_{0}^\infty \; e^{-q.t} \; \frac{t^{-s-1}}{(-s-1)!} \; dt$$

via analytic continuation. If $q_n = D_x^n$, the action of the integral on $H(x) \frac{x^\alpha}{\alpha!}$, where $H(x)$ is the Heaviside step function, gives a classic fractional calculus in terms of an analytically-continued (AC) Mellin convolution (essentially that for the AC Euler beta function integral) for the interpretation of $D_x^{s}$ for real or complex $s$.

See Boole, Blissard, Sylvester, Cayley, Appell, (Jensen?), Heaviside, Steffensen, Sheffer, Pincherle, Bell, Riordan, Rota, Taylor, Roman, Ray, and Lenart for contributions to and influences on the development of the umbral symbolic calculus.

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To resolve the ambiguity when using multiple instances of $\pm$ within a single expression, I use $\pm_n$ and $\mp_n$. $\pm_a$ must be equal to $\pm_b$ iff $a=b$.

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I recently saw the following notation in the context of divisors on algebraic varieties, and I liked it very much.

Suppose that $D$ and $E$ are reduced divisors on a normal algebraic variety $X$. One can use $D \vee E$ to denote the reduced divisor with support equal to $D + E$ and $D \wedge E$ to denote $(D + E) - (D \vee E)$. I could imagine variants on this if $D$ and $E$ are non-reduced (involving taking max's, respecitvely mins, of the divisors component-wise).

EDIT: I'm slightly curious as to why this was downvoted. I guess it's too common to be interesting?

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    $\begingroup$ It is not me , I do not know algebraic variety, but as a guess may be there is some order there and so you have an inf and sup or even a lattice that would fully justify these notation and be rather common at that. $\endgroup$ Commented Nov 23, 2010 at 23:54
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Has anyone come across any more similar examples of good notation that should be better known?

Some interesting glyphs:

  1. Combinatorial Principles in Set Theory:

  2. Bisimulation:

    • Given two states p and q in S, p is bisimilar to q, written p ~ q, if there is a bisimulation R such that (p,q) is in R.
  3. Boxplus operator in Coding Theory

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    $\begingroup$ I always considered 1. to be a prototypical example of bad notation. $\endgroup$ Commented Dec 19, 2011 at 13:27
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    $\begingroup$ @EmilJeřábek, I think that (2) has to be a still more prototypical example, in the sense that, without additional context, no two people will agree which equivalence relation is denoted by $\sim$ (although I guess we all agree it is an equivalence relation?). $\endgroup$
    – LSpice
    Commented Jul 7, 2019 at 12:31
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In algebra, it is very useful to write $J\cap A$ for the inverse image of an ideal $J$ in a ring $B$ under a homomorphism $f:A\to B$, rather than $f^{-1}(J)$. I normally also omit the morphism and write $IB$ for the ideal generated by the image in $B$ of an ideal $I$ in $A$, rather than $f(I)B$.

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I like the notation $A\mathrel{\in\in}\mathcal C$ for objects (rather than morphisms) in a category (not my own invention).

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    $\begingroup$ It looks like a typo. $\endgroup$ Commented Jan 28, 2018 at 0:37
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The notation of $u \mathbin{[\wedge]} v$ for the product of Lie-algebra valued differential forms (I prefer this to another variant $[u \wedge v]$).

Writing the tangent natural tranformation as $\tau: T \rightarrow \operatorname{Id}$ which expands to $\tau_M : TM \rightarrow M$.

I've seen some category theorists write $\operatorname{Hom}_A[a,b]$ for the homset for a category $A$, which gets a bit long-winded when $A$ is a category with a long name like $\mathrm{Ring}$ or $R\text-\mathrm{Mod}$. It seems much more natural to write $A[a,b]$.

Personally, I like $\bar{\mathbb{R}}$ to write the order completions of the reals. It's less clumsy than $\mathbb{R} \cup \infty$.

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    $\begingroup$ Unfortunately, $u [\wedge] v$ u [\wedge] v by itself doesn't space well; you have to manually tell TeX you've still got a binary operator with $u \mathbin{[\wedge]} v$ u \mathbin{[\wedge]} v. I edited accordingly. $\endgroup$
    – LSpice
    Commented Dec 17, 2021 at 21:53
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Many textbooks say that the normal distribution is the one whose density is $$ x\mapsto \frac1{\sqrt{2\pi}} \times \frac1\sigma \exp\left( -\frac12 \left( \frac{x-\mu}\sigma \right)^2 \right) $$ and the gamma distribution is the one whose density is $$ x\mapsto \frac1{\Gamma(\alpha)} \times \lambda^\alpha x^{\alpha-1} e^{-\lambda x} \text{ for } x>0$$ and the Pareto distribution is the one whose density is $$ x\mapsto \frac{\alpha\kappa^\alpha}{x^{\alpha+1}} \text{ for } x>\kappa $$ etc.

I prefer to say that the normal distribution is $$ \frac1{\sqrt{2\pi}} \times \exp\left( -\frac12\left( \frac{x-\mu}\sigma\right)^2 \right)\, \frac{dx}\sigma $$ and the gamma distribution is $$ \frac1{\Gamma(\alpha)} \times (\lambda x)^{\alpha-1} e^{-\lambda x} (\lambda \, dx) \text{ for } x>0 $$ and the Pareto distribution is $$ \frac\alpha{(x/\kappa)^{\alpha+1}} \, \frac{dx}\kappa \text{ for } x>\kappa, $$ and so on.

This shows that each scale parameter, or its reciprocal, the rate parameter or intensity parameter, goes with an $\text{“} x\text{,”}$ and suggests a substitution to be used when thinking about integrating.

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Many years ago, I invented the notation $\mathcal{Lex}_{T}(X)$ as the function equal to $1$ if and only if the consideration of $X$ in the theory $T$ entails no contradiction and $0$ otherwise. Lex is both "law" in Latin and a shortcut for "Logical existence", which in some sense is the only law of mathematics.

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    $\begingroup$ Why the down vote? Could someone familiar with the subject please explain. $\endgroup$
    – Ben McKay
    Commented Jul 15, 2017 at 10:27
  • $\begingroup$ I'm afraid nobody works on this. I got interested in the subject more than 15 years ago, after a friend of mine starting to study maths told me something like "the integers of the empty set are even" and "the integers of the empty set are odd" were both equally true. I felt shocked and tried to figure out a way to forbid the consideration of "integers of the empty set" and other impossible concepts. $\endgroup$ Commented Jul 15, 2017 at 10:37
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    $\begingroup$ Isn't this just $\operatorname{Con}(T \cup \{X\})$ or am I misinterpreting? $\endgroup$
    – user76284
    Commented Oct 27, 2019 at 0:12
  • $\begingroup$ It seems $\operatorname{Con}$ is a unary predicate, while $\mathcal{Lex}$ is a map with values in $\{0,1\}$. But otherwise, the idea is the same. $\endgroup$ Commented Oct 27, 2019 at 9:32
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I like the notation $f:A\cong\subseteq B$ for "$f$ is an embedding of $A$ into $B$." The idea is that the relation of embeddability is obtained by composing the relations "isomorphic to" and "substructure of."

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  • $\begingroup$ Hmm, others seem to disagree. What do you think of $\hookrightarrow$? $\endgroup$
    – David Roberts
    Commented Nov 24, 2011 at 23:11
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    $\begingroup$ @David: I tend to use $\hookrightarrow$ for maps that are literally inclusions. $\endgroup$ Commented Nov 25, 2011 at 4:00
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    $\begingroup$ I've mostly seen people use $\subset$ or $\subseteq$ for literal inclusions and $\hookrightarrow$ for embeddings (or whatever kind of injection is suitable). Reserving $\hookrightarrow$ for literal inclusions seems kind of pointless when $\subset$ exists. $\endgroup$ Commented Nov 25, 2011 at 8:34
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    $\begingroup$ ... and then you can decorate the arrow with o or | to incorporate meaning like "open immersion" or "closed immersion". $\endgroup$ Commented Dec 19, 2011 at 10:43
  • $\begingroup$ @KonradVoelkel, you use $\overset|\hookrightarrow$ for a closed immersion? Is that standard? $\endgroup$
    – LSpice
    Commented Dec 17, 2021 at 1:59
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$x\gtrless 0$ to denote that $x\in\mathbb{R}\setminus\{0\}$. Or, if $x\notin\mathbb{R}$ but rather $x\in\mathbb{Z}\setminus\{0\}$ for example, then we write $x\in\mathbb{Z}_{\gtrless 0}$. I prefer the $\gtrless$ notation because it is simpler and more understandable when first met with the eye, and I hope it is set in stone sooner or later.

I also came across the following notation: $$\sum_p'f(x).$$ The little dash $'$ on top of the sigma $\Sigma$ denotes that $p$ is prime. I like this, but I don't feel this is necessary because we can write $$\sum_{p \ \text{prime}}f(x)$$ but when looking at both conventions, the former looks a lot neater.

Also, we have notation $>$, $\gg$ and $\ggg$ with $<$, $\ll$, and $\lll$ but I was thinking, is there a notation to denote that a value $a$ is not much less than a value $b$? I came up with $$a\overline{<} b\tag*{$a$ is not much less than $b$}$$ $$a\overline{>}b\tag*{$a$ is not much greater than $b$}$$

I have also seen that the symbol for concatenation is sometimes $||$, but if I was to see $$A \ || \ B$$ then my first thought would be $A$ is parallel to $B$, but that is just me. With some research, I discovered that there is however some kind of official notation, such that $A^\frown B$ but I don't like it.

I also went extreme and invented this: $$\mathop{\LARGE\Omega}_{\substack{x=k \\ \\ R}}^{x_0} (x, y)$$ to define a set of coordinates; a relation. Here, $x\to x_0$ and $R$ simply denotes the rule, $y = \cdots$. This way, we can write stuff like $$\mathop{\LARGE\Omega}_{\substack{x=36 \\ \\ y = 2x+1}}^{144}(x, y)$$ And then if we don't have a rule, but something like $y\geq0$ for example, then we can write a double index to refer to what value $y$ tends towards, namely $y_0$.

Oh and I almost forgot, I thought that maybe we can symbolise contradiction? For instance, I want to prove that $\sqrt{2}$ is irrational. I would first suppose it is rational, then come to a conclusion that contradicts this statement. Since most of us use $\Box$ in notation of completing a proof, I decided that I could use $\Diamond$ in notation of a contradiction. I thought about it because it is like a titled box $-$ a bit like approaching the proof $\Box$ on a different angle $\Diamond$, if you get what I am saying.

I am not taking this too seriously, for I was just being creative, but I believe there's nothing wrong in trying new things out. Any thoughts?

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    $\begingroup$ Re: your second-to-last paragraph, there are multiple symbols used for proof-by-contradiction - my personal favorite being "$\perp$," but "$\Rightarrow\Leftarrow$" is also common, as is some form of "lightning bolt." I would strongly object to "$\Diamond$," however, given the meaning of $\Diamond$ and $\Box$ in modal logic. $\endgroup$ Commented May 13, 2019 at 18:08
  • $\begingroup$ Is your $\Omega$ thing any different than $ \{(x,y) \colon 36 \leq x \leq 144, y=2x+1\}$? $\endgroup$ Commented May 13, 2019 at 19:18
  • $\begingroup$ @ZachTeitler nah, it's the same thing. The $\Omega$ thing is easier to write, but the "normal way of writing it" is easier to read ;) $\endgroup$
    – Mr Pie
    Commented May 13, 2019 at 21:30
  • $\begingroup$ Instead of typing A\ ||\ B so that you see $A\ ||\ B,$ if you type A\parallel B then you see $A\parallel B.$ Is there anyone to whom that doesn't look better? $\endgroup$ Commented Jan 21, 2022 at 2:59
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