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This is a generalisation of my earlier question about generators for the level 1 Hecke algebra.

Let $\Gamma$ be a congruence subgroup of $\operatorname{SL}_2(\mathbb{Z})$, and $k \ge 1$ an integer. There's an explicit bound $S$ (the "Sturm bound") known such that if $f \in M_k(\Gamma)$ (the space of modular forms of weight $k$ and level $\Gamma$) satisfies $a_n(f) = 0$ for $0 \le n \le S$, then $f = 0$, where $a_n(f)$ denote the coefficients of the $q$-expansion of $f$ (at the cusp $\infty$).

Since $M_k(\Gamma)$ is finite-dimensional and doesn't contain any nonzero constant functions, there must actually exist some $S'$ such that if $a_n(f) = 0$ for $1 \le n \le S'$ (but with no assumption on $a_0(f)$), then in fact $f = 0$. Can one give an effective upper bound on $S'$ (in terms of $k$ and the index $[\operatorname{SL}_2(\mathbb{Z}) : \Gamma]$)?

I'd be interested to know the answer to this even for the special case $\Gamma = \Gamma_0(N)$ or $\Gamma_1(N)$. For these groups it is equivalent to asking that the Hecke algebra acting on $M_k(\Gamma)$ is spanned by the operators $T_1, \dots, T_{S'}$ (hence the title of the question).

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  • $\begingroup$ @David: if you don't want anyone to answer the question you should delete it. $\endgroup$ Commented Oct 21, 2010 at 14:18
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    $\begingroup$ I've decided to undelete this old question -- I did delete it because I wanted to set it as a student project, but the student didn't solve it. $\endgroup$ Commented Jul 23, 2013 at 19:45
  • $\begingroup$ Hmmm... isn't it called a "Sturm bound"? $\endgroup$ Commented Jul 24, 2013 at 4:55
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    $\begingroup$ David, do you know a good reference for sturm bounds? $\endgroup$
    – Joël
    Commented Jul 24, 2013 at 12:49
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    $\begingroup$ Joel: see e.g. wstein.org/books/modform/modform/newforms.html#sturm-s-theorem. $\endgroup$ Commented Jul 24, 2013 at 20:07

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