This question is inspired but not directly related to this recent Stanley's MO post.
The descent set $D(w)$ of a permutation $w=a_1 a_2\cdots a_n\in\frak{S}_n$ (the symmetric group on $\{1,\dots,n\}$) is defined by $D(w)=\{ 1\leq i\leq n-1\,:\, a_i>a_{i+1}\}$. Denote the cardinality of $D(w)$ by $des(w)$.
The Eulerian polynomials are known to express $$A_n(x)=\sum_{w\in\frak{S}_n}x^{des(w)}$$ whose exponential generating function is given by $$\sum_{n\geq0}A_n(x)\,\frac{z^n}{n!}=\frac{1-z}{z-e^{(1-z)x}}.$$ Suppose we wish to refine this by including the cycle-type of each permutation.
QUESTION. Is there a generating function for the sum $$\sum_{w\in\frak{S}_n}x^{des(w)}\,t_1^{a_1}t_2^{a_2}\cdots t_n^{a_n}$$ where $(a_1,\dots,a_n)$ is the cycle-type of $w$? Caveat. the $a_i$'s are non-negative integers.
Examples. The first few polynomials for $n=1, 2, 3$ and $4$: \begin{align*} &t_1 \\ &t_1^2+t_2x \\ &t_1^3+(2t_1t_2+2t_3)x+t_1t_2x^2 \\ &t_1^4+(3t_1^2t_2+4t_1t_3+t_2^2+3t_4)x+(3t_1^2t_2+4t_1t_3+t_2^2+3t_4)x^2+t_2^2x^3. \end{align*}