We know the bordism group for oriented smooth differentiable structures such as $\Omega_d^{SO}$ that requires the special orthogonal group structure on the tangent bundle $TM$ of manifold $M$.
$$\Omega_0^{SO}=\mathbb{Z}$$ $$\Omega_1^{SO}=0$$ $$\Omega_2^{SO}=0$$ $$\Omega_3^{SO}=0$$ $$\Omega_4^{SO}=\mathbb{Z}$$ $$\Omega_5^{SO}=\mathbb{Z}/2$$ $$\Omega_6^{SO}=0$$ $$\Omega_7^{SO}=0$$ $$\Omega_8^{SO}=\mathbb{Z} \oplus \mathbb{Z}$$ $$\Omega_9^{SO}=\mathbb{Z}/2 \oplus \mathbb{Z}/2$$ $$\Omega_{10}^{SO}=\mathbb{Z}/2$$ $$\Omega_{11}^{SO}=\mathbb{Z}/2$$
Some of the cobordism invariants for these bordism groups only require the Stiefel-Whitney class $w_j(TM)$. But $w_j(TM)$ can be defined on oriented triangulable manifolds without smooth differentiable structures. So those cobordism invariants may still survive when we loosen the condition to study the oriented triangulable manifolds without smooth differentiable structures.
Do we know any bordism theory for oriented triangulable manifolds without smooth differentiable structures that produces the similar bordism groups as above, but only maintain those cobordism invariants that only require oriented triangulable manifolds (such as those only require Stiefel-Whitney class $w_j(TM)$)? That is, could we remove the $SO$ structure above, and only keep the triangulation, say $trg$, and study its bordism group? I expect something like:
$$\Omega_5^{triag}=\mathbb{Z}/2, \text{: cobordism invariant: $w_2w_3$}$$
$$\Omega_9^{triag}=\mathbb{Z}/2 \oplus \dots \text{: cobordism invariant: $w_4w_5$}$$
$$\Omega_{13}^{triag}=\mathbb{Z}/2 \oplus \dots \text{: cobordism invariant: $w_6w_7$}$$
$$\Omega_{4k+1}^{triag}=\mathbb{Z}/2 \oplus \dots \text{: cobordism invariant: $w_{2k}w_{2k+1}$, for $k\geq1$}$$
I suppose the Piecewise Linear PL is similar to what I want. I do not think I am considering the topological manifold Top. But I do not require the smooth structure, nor the $SO$ or $O$ tangential structure. But I am not sure that the Stiefel-Whitney class $w_j(TM)$ requires the PL structure. The Stiefel-Whitney class $w_j(TM)$ may require only the triangulation and branching rule on manifold $M$.