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I want to know if the following theory stand a chance of being consistent?

$Language:$ Mono-sorted first order predicate logic + primitives of equality $``="$ and class membership $``\in"$:

Define: $set(x) \iff \exists y \, (x \in y)$

Axioms:

Extensionality: $\forall z ( z \in x \leftrightarrow z \in y) \implies x=y$

Class Comprehension: $\exists x \forall y (y \in x \iff set(y) \phi)$; for any formula $\phi$ in which $``x"$ doesn't occur.

Define: $x=V \equiv_{df} \forall \text { set } y \, (y \in x)$

Sets: $\sf ZFC$$^V$

That is: all axioms of $\sf ZFC$ written with all of their quantifiers bounded $``\in V"$.

Size: $\forall x \in V (|x| \leq \aleph_\omega)$

Exchange: $\forall a,b \in V: |a|=|b| \to \\\exists f (f: a \to b \land bijection(f) \land \\ \forall k \in V [k \subseteq a \to f``k \in V ] \, \land \\\forall l \in V [l \subseteq b \to f^{-1} ``l \in V] )$

Where: $f``x = \{f(y): y \in x\}$, and $f^{-1}= \{\langle b,a \rangle: \langle a, b \rangle \in f\}$

The point here is that the last axiom does add sets through the use of an external function! So sets are not just left a lone to be built after the set world ZFC rules. No! Sets can be constructed after external functions here.

Can this theory be consistent???

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  • $\begingroup$ To clarify, in the size axiom the functions witnessing $\vert x\vert\le\aleph_\omega$ need not in general be elements of $V$, but $\aleph_\omega$ is the thing $V$ thinks is $\aleph_\omega$, correct? $\endgroup$ Commented Apr 6, 2021 at 1:50
  • $\begingroup$ @NoahSchweber, Yes! For example there is no bijection in $V$ from $\aleph_\omega$ to $\aleph_{\omega+1}$, but there is one externally! So there is a subset of $V$ that is a bijection from $\aleph_\omega$ to $\aleph_{\omega+1}$ yet it is NOT an element of $V$. $\endgroup$ Commented Apr 6, 2021 at 11:28

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