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Given a closed set $\varnothing\neq E\subset\mathbb{R}^n$, let $\operatorname{Unp}(E)$ be the set if points $x\in\mathbb{R}^n$ for which there is a unique point $y\in E$ nearest to $x$. Clearly $E\subset\operatorname{Unp}(E)$. On the other hand, it is known that the Lebesgue measure of the set $\mathbb{R}^n\setminus\operatorname{Unp}(E)$ equals zero, $\lvert\mathbb{R}^n\setminus\operatorname{Unp}(E)\rvert=0$ (cf. Set of points with a unique closest point in a compact set).

Erdős [1] proved a much stronger result:

The set $\mathbb{R}^n\setminus\operatorname{Unp}(E)$ is contained in the sum of countably many surfaces of finite $(n-1)$-dimensional measure.

This is a beautiful and I think, not very well known theorem. However, from the results existing in the literature one can conclude:

Theorem. For any closed set $E\subset\mathbb{R}^n$ there are countably many $C^2$-graphs $\{ G_j\}_{j=1}^\infty$ such that $$ \mathcal{H}^{n-1}\Bigl((\mathbb{R}^n\setminus\operatorname{Unp}(E))\setminus\bigcup_{j=1}^\infty G_j\Bigr)=0. $$

Here $\mathcal{H}^{n-1}$ stands for the Hausdorff measure and by a $C^2$-graph I mean the graph of a $C^2$ function $f:\mathbb{R}^{n-1}\to\mathbb{R}$. $$ \{x\in\mathbb{R}^n\mathrel: x_i=f(x_1,\dotsc,x_{i-1},x_{i+1},\dotsc,x_n)\}. $$

While the theorem can be concluded from what is in the literature, I was not able to find a straightforward reference to this statement. I think this result is of considerable interest, but most of people who would find it interesting would have difficulty to find it in the literature.

Question. Do you know if this result (or something very similar) has been published anywhere?

[1] P. Erdős, On the Hausdorff dimension of some sets in Euclidean space. Bull. Amer. Math. Soc. 52 (1946), 107-109.

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    $\begingroup$ @DanieleTampieri Thank you. A correction has been made. $\endgroup$ Commented Nov 27, 2020 at 21:14
  • $\begingroup$ Possibly Luděk Zajíček's work involving delta-convex mappings contains this result (see also this less restrictive search and this search involving cone porous sets), but much of it involves intricate technicalities and is devoted to infinite dimensional settings, neither of which I know much about. $\endgroup$ Commented Nov 28, 2020 at 8:05
  • $\begingroup$ @DaveLRenfro Thank you. That was helpful. Indeed, when I said that it can be concluded from the existing results, one of them was to Luděk Zajíček. I agree, almost everything is written in Banach spaces which is not helpful. $\endgroup$ Commented Nov 28, 2020 at 13:56
  • $\begingroup$ Incidentally, Pointwise bounded approximation and hypodirichlet algebras by Theodore William Gamelin and John Brady Garnett [Bull. AMS 77 #1, January 1971, pp. 137-141 (online data has incorrect last page value)] defines the following unusual (to me, at least) $\sigma$-ideal on p. 138: A curvilinear null set is a subset of zero outer length lying on a twice continuously differentiable curve. A $\sigma$-curvilinear null set is a countable union of curvilinear null sets. $\endgroup$ Commented Nov 28, 2020 at 16:18
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    $\begingroup$ @LeoMoos He does not say it explicitly, but I think that follows from the proof. He is using a "well known lemma" that nobody knows these days. The lemma has a vague statement about regularity of surfaces, but the proof in amazing Saks' Theory of the integral says that the surfaces are graphs of Lipschitz functions. $\endgroup$ Commented Dec 1, 2020 at 14:34

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I used such results in my thesis on the topology of singularities arising in various optimal transport programs (Sections 4.2-3). Especially useful was the following article of G. Alberti:

Alberti, Giovanni. "On the structure of singular sets of convex functions." Calculus of Variations and Partial Differential Equations 2.1 (1994): 17-27.

Alberti's Theorem: If $f:\mathbb{R}^n \to \mathbb{R}$ is proper lower semicontinuous convex function, then the subsets $$S^k(f):=\{x\in \mathbb{R}^n ~|~\dim_{\mathscr{H}} \partial_{\bullet} f \geq k\}$$ can be covered by countably many $(n-k)$-dimensional DC-manifolds.

Here $\partial_{\bullet} f $ is the local subdifferential of $f$.

The assumption that the function $f$ is convex is not as restrictive as it appears, for we can always replace $f$ with a locally semiconvex function. See Proposition 4.3.4. in my thesis for details. And if the closed set $E$ is locally compact (of course it is), then $dist_E$ becomes locally semiconvex, and we can apply Alberti's theorem to conclude that indeed the medial axis (or $\mathbb{R}^n-Unp(E)$ in the OP's notation) has Hausdorff dimension $\leq n-1$ and can be covered by countably many $(n-1)$-dimensional $DC$-manifolds.

Related results occur in R.J.McCann's and J. Kitagawa's article "Free Discontinuities in Optimal Transport". https://arxiv.org/abs/1708.04152

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The following result can be found in

D. H. Fremlin, Skeletons and central sets, Proc. London Math. Soc. (3) 74 (1997), 701–720.

Let $\Omega$ be an open proper subset of $\mathbb{R}^n$, where $n > 1$. Its skeleton is

$$R:=\{ x \in \Omega: \text{ there are distinct } y, y'\in \mathbb{R}^n \setminus \Omega \text{ such that } \rho( x , y ) =\rho( x , y ) = \rho( x , \mathbb{R}^n \setminus \Omega)\},$$ where we write $\rho$ for the Euclidean metric on $\mathbb{R}^n$.

Theorem 1G: Let $\Omega$ be an open proper subset of $\mathbb{R}^n$. Then its skeleton $R$ is the union of a sequence of closed sets each of which is Lipschitz isomorphic to a subset of $\mathbb{R}^{n-1}$. Consequently , the dimension of $R$ is at most $n-1$, whether we mean inductive dimension , covering dimension , Hausdorff dimension or Minkowski dimension.

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  • $\begingroup$ Thank you for the reference. Clearly, Fremlin was not aware of the work of Erdos. $\endgroup$ Commented Feb 5, 2021 at 21:19

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