11
$\begingroup$

Let $X$ be a finite (CW or simplicial - doesn't matter) complex and consider the space of all compact subspaces of $R^\infty$ which are homotopy equivalent to $X$, topologized say as a subspace of the space of all compact subspaces of $R^\infty$ with the Hausdorff metric. What is known about this space? I vaguely recall that it is related to Waldhausen's $A$-theory - are there any references for that?

Motivation: if one instead looks at the space of all subspaces homeomorphic to or respectively diffeomorphic (if $X$ is a manifold) to $X$ one has a model for $BHomeo(X)$ or $BDiff(X)$ (since the corresponding space of embeddings of $X$ in $R^\infty$ is weakly contractible and this space is the quotient of the space of embeddings by the homeo/diffeo group). I have been having fun lately thinking about these models when $X$ is a finite set of points or a surface. This space of subspaces homotopy equivalent to $X$ is different - in particular I do not see it (directly anyways) as a model for $BHomotopySelfEquiv(X)$ - so I'd like to know more what is known about it.

$\endgroup$

1 Answer 1

4
$\begingroup$

To me, Hausdorff metric is an unaccustomed way of making such a space of spaces. I think I don't trust it because fixing a homotopy type gives you a set that is neither closed nor open in general.

But yes I believe the picture is that some kind of "space of spaces of homotopy type $X$" is closely related to $A(X)$.

Let's start with smooth manifolds, but of codimension zero. For a fixed $n$ and a finite complex $K\subset \mathbb R^n$, let $M_n(K)$ be the space of smooth compact $n$-manifolds $N\subset \mathbb R^n$ containing $K$ in the interior as a deformation retract. (Let's say, the simplicial set where a $p$-simplex is a suitable thing in $\Delta^p\times \mathbb R^n$ such that the projection to $\Delta^p$ is a smooth fiber bundle.) You can map $M_n(K)\to M_{n+1}(K)$ by crossing with $[-1,1]$ (and doing something about corners), and you can consider the (homotopy) colimit over $n$. Using the classification of $h$-cobordisms you can work out that the set of components is the Whitehead group of $K$. The loopspace of one component is the smooth stable pseudoisotopy space of $K$. To get the idea, think of the case when $K$ is a point: the space $M_n(K)$ is then, after you discard extraneous components corresponding to cases where the boundary is not simply connected -- which were going to go away anyway upon stabilizing over $n$ -- your quotient of {embeddings $D^n\to\mathbb R^n$}~$O(n)$ by {diffeomorphisms $D^n\to D^n$}. It's also a kind of "space of all $h$-cobordisms on $S^{n-1}$, and thus a delooping of the (unstable) pseudoisotopy space of $S^{n-1}$.

When $K$ is more complicated than a point, it's important to distinguish between the space of all blah blah blah containing $K$ as a deformation retract and the space of all blah blah homotopy equivalent to $K$; they differ by the space of homotopy equivalences $K\to K$.

There is a similar story for the piecewise linear or topological case.

The piecewise linear manifold version of this construction can, I believe, be shown to be equivalent to a non-manifold construction more like what you asked about: some kind of "space of compact PL spaces in $\mathbb R^n$ containing a fixed $K$ as deformation retract".

Waldhausen tells us that the stable smooth construction above and the stable PL construction above are respectively (the underlying spaces of spectra which are) the fiber of a map from the suspension spectrum of $K\cup{point}$ to $A(K)$, and the fiber of a map from $A(*)\wedge (K\cup{point})$ to $A(K)$.

$\endgroup$
2
  • $\begingroup$ Yes, I think this story is what I am interested in. To follow up on your first comments, it seems to me that the Hausdorff metric restricts to the standard topology on the space of subspaces homeo to a given (compact) one (Emb(X, R^\infty)/Homeo(X)) - am I wrong on that? Though that doesn't preclude it from giving something funny when we are just restricting the homotopy type of the subspace. I wonder what happens when you think of submanifolds (of a fixed dimension?) homotopy equivalent to a given one. $\endgroup$
    – Dev Sinha
    Commented Aug 27, 2010 at 21:11
  • $\begingroup$ Suppose M and M′ are closed manifolds, h-cobordant but not simple homotopy equivalent, and of not too small dimension. An h-cobordism between them can be put inside M×ϵ, making M′ arbitrarily close to M in your sense. It seems to me that in this way you can produce a continuous path in your Hausdorff metric space from M to M'. But I don′t want $M$ and $M'$ to be in the same component. $\endgroup$ Commented Aug 30, 2010 at 1:54

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .