Here: https://www.mathematik.uni-kl.de/~gathmann/class/alggeom-2002/alggeom-2002-c9.pdf, on pages: $ 1 $ and $ 2 $, we find the following paragraph:

For any scheme of finite type over a ground field and any integer $ k>0 $, we will define the so-called Chow groups $ A_k (X) $ whose elements are formal linear combination of $ k $ -dimentional closed subvarieties of $ X $, modulo ''boundaries'' in a suitable sense. The formal properties of this groups $ A_k (X) $ will be similar to those of homology groups. Il the ground field is $ \mathbb{C} $, you might even thought of the $ A_k (X) $ as being ''something like'' $ H_{2k} (X , \mathbb{Z} ) $, although these groups are usually different. But, there is a map $ A_{k} (X) \to H_{2k} ( X , \mathbb{Z} ) $, so you can think of elements in the Chow groups as something that determines a homology class, but this map is in general neither injective nor surjective.


  • After reading this block, and since it is said in this block that, in general, the morphism $ A_k (X) \to H_{2k} (X, \mathbb {Z}) $ is neither injective, nor surjective, can you give me some examples of $ A_k (X) \to H_{2k} (X, \mathbb{Z}) $ maps that are not injective, or that they are not surjective where : $ 4 \leq 2k \leq n-4 $ and $ n - 4 > 0 $, and $ n $ is the dimension of $ X $ ?

Thanks in advance for you help.

  • 6
    $\begingroup$ Well, the image of the cycle class map has to be contained in $H^{(k,k)}(X,\mathbb{Z}). $\endgroup$
    – Qfwfq
    Feb 3, 2020 at 15:44
  • 1
    $\begingroup$ For obstructions to infectivity, look up the generalized Bloch conjecture. For obstructions to surjectivity @Qfwfq's comment should be the only rational obstruction; there are other failures of surjectivity known (look up papers giving counterexamples to the integral Hodge conjecture). At the end of the day, assuming Hodge and generalized Bloch, there is a complete characterization of when injectivity/surjectivity fails rationally. $\endgroup$
    – dhy
    Feb 3, 2020 at 20:26
  • $\begingroup$ Thank you Qfwfq and dhy. It's clear now. :-) $\endgroup$
    – YoYo
    Feb 3, 2020 at 20:51

1 Answer 1


If $C$ is a smooth projective curve of genus $g \geq 3$ and $J(C)$ is the Jacobian of $C,$ then an Abel curve $C \subset J(C)$ is not algebraically equivalent to its image $-C$ under the negation automorphism, even though $C$ is homologically equivalent to $C.$ This was proved by Ceresa in the paper


EDIT: Ceresa also shows in this paper that if $C$ is generic and $1 \leq k \leq g-2$, the cycles $W_k$ and $-W_k$ in $J(C)$ (recall that $W_k$ is the cycle parametrizing effective line bundles of degree $k$ on $C$) are algebraically independent (although they are homologically equivalent). This gives examples of non-injectivity for higher-dimensional cycles.

  • 2
    $\begingroup$ It should be $g\ge 3$. $\endgroup$
    – AG learner
    Feb 3, 2020 at 16:35
  • $\begingroup$ @AGlearner Fixed, thanks! $\endgroup$ Feb 3, 2020 at 16:46
  • 1
    $\begingroup$ Thank you @Yusuf. :-) $\endgroup$
    – YoYo
    Feb 3, 2020 at 20:52

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