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I am struggling to reconcile the two definitions of smooth k-manifold in $R^n$ from M.Spivaks Calculus on Manifolds (pg 109) and J.W Minor's Topology from differential point of view (pg 01).

Milnor's Definition

The key concept in Milnor's definition is smooth function, between arbitrary subsets of Euclidean space. If $f:X \to Y$ and $X \subset R^n, Y\subset R^m$. Then $f$ is smooth if for each point $p \in X$, there is a an open neighbourhood $U \subset R^n$ and a $C^\infty$ function $F:U \to V$ ($V \subset R^m$ is open) that is compatible (an extension of) with $f$. i.e, $F_{|X \cap U} = f_{|X \cap U}$. Now the diffeomorphism between subsets becomes smooth function that has a two-sided inverse which is also smooth.

The definition of a k-manifold is now made quite naturally as a subset of $R^n$ which is diffeomorphic to an open subset in $R^k$.

Spivak's Definition.

Spivak only considers invertible (having two-sided inverse) $C^\infty$ function between open subsets and calls this a diffeomorphism, of course this agrees with Milnor's definition when $X, Y$ above are open subsets. Then Spivak's defines the smooth k-manifold using this diffeomorphism. A subset $M\in R^n$ is a k-manifold if the following criteria are satisfied.

  • For any $p \in M$, there is an open neighbourhood of $p$, $U\subset R^n$ and a diffeomorphism, $f:U \to V$, $V$ open subset in $R^n$ satisfying,

  • $f(M\cap U) = V \cap ( R^k \times \{0\} )$


My thoughts

I can see that "Spivak" $\implies $ "Milnor". But I don't find the other direction trivial. Assuming Milnor's definition holds, there is a function $f:M \to V$. Where $M$ is the manifold and $V$ is an open subset of $R^k$ and there is a two-sided inverse to this function $f^{-1}$. Since they are both smooth (according to the definition of Milnor), given a point $p \in M$, we can construct the following $C^\infty$ functions (that reduce to $f, f^{-1}$ where they are commonly defined), for an open neighbourhood $U \subset R^n$ of $p$ and an open set $V' \subset R^k$.

  • $F:U \to V'$ ($V'$ open in $R^k$)

  • $G:V' \to U$

Clearly, $F$ is not injective and $G$ is not onto in general ($n \neq k$). How can one build a $C^\infty$ invertible map that Spivak uses in his definition from these functions, i.e by extending the dimension of domain/range appropriately. I am quite puzzled. Perhaps, I am missing something very trivial. I will really appreciate any help since I am doing a self-study. Thanks in advance.


Milnor's Book: http://webmath2.unito.it/paginepersonali/sergio.console/Dispense/Milnor%20Topology%20from%20%23681EA.pdf

Spivak's Book: http://strangebeautiful.com/other-texts/spivak-calc-manifolds.pdf

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    $\begingroup$ I don't have Milnor's book here, but I think it should have locally diffeomorphic (otherwise we miss e.g. closed curves) $\endgroup$ Commented Dec 4, 2019 at 4:59
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    $\begingroup$ @PietroMajer Thanks for the comment. Here is a link to Milnor's book: webmath2.unito.it/paginepersonali/sergio.console/Dispense/…. I am not quite sure what "locally" diffeomorphic is? $\endgroup$ Commented Dec 4, 2019 at 5:31
  • $\begingroup$ @PietroMajer Ah! I see what you mean locally diffeomorphic. I think it is, it happens in the definition of smooth maps. $\endgroup$ Commented Dec 4, 2019 at 6:31
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    $\begingroup$ But any point has a nbd with its diffeo. Here (in both definitions) "locally diffeomorphic" refers to: Any point of $M$ has an open nbd $U$ in $\mathbb{R}^n$, and a diffeo $\phi:U\to V$ onto another open subset $V$ of $\mathbb{R}^n$, that flatten the trace of $M$ in $U$, that is $\phi(U\cap M)=V\cap E$, $E$ being a $k$-dimensional subspace. An equivalent definition would be: $M$ is locally a graph of a smooth function of $k$ variables (with value in the span of the other $n-k$, so that the graph is indeed a subset of $\mathbb{R}^n$) $\endgroup$ Commented Dec 4, 2019 at 7:56

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